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Zina [86]
2 years ago
5

Bob has a brother, jim, who has a daughter named bertha. Bertha's daughter, jennifer, has a sister named penny. which of the fol

lowing indicates the relationship between jim and penny?
Physics
2 answers:
sammy [17]2 years ago
7 0
Grandparent and grandchild
Kryger [21]2 years ago
4 0

The correct answer is - grandparent and grandchild.

Jim has a daughter, The name of his daughter is Bertha. Bertha also has children, two daughters, one of which is Penny. Since Jim's daughter is Bertha, than the children of Bertha are his grandchildren, thus Penny is Jim's grandchild, and Jim is Penny's grandparent.

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The three forces acting on a hot-air balloon that is moving vertically are its weight, the force due to air resistance and the u
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Let
upthrust = T
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T+F-W=0......................(1)

Let w=weight of material dumped so that balloon now travels upwards at constant speed.
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The Newton's equation now reads
T-F-(W-w)=0................(2)

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Which of the following statements accurately describes the atmospheric patterns that influence local weather?
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4 0
1 year ago
A particle in the first excited state of a one-dimensional infinite potential energy well (with U = 0 inside the well) has an en
nataly862011 [7]

Answer:

The energy of this particle in the ground state is E₁=1.5 eV.

Explanation:

The energy E_{n} of a particle of mass <em>m</em> in the <em>n</em>th energy state of an infinite square well potential with width <em>L </em>is:

                                                    E_{n}=\frac{n^{2}h^{2}}{8mL^{2}}

In the ground state (n=1). In the first excited state (n=2) we are told the energy is E₂= 6.0 eV. If we replace in the above equation we get that:

                                                    E_{1}=\frac{h^{2}}{8mL^{2}}            

                                                    E_{2}=\frac{h^{2}}{2mL^{2}}

So we can rewrite the energy in the ground state as:

                                                   E_{1}=\frac{1}{4}(\frac{h^{2}}{2mL^{2}})

                                                      E_{1}=\frac{1}{4} E_{2}

                                                   E_{1}=\frac{1}{4} ( 6.0\ eV)

Finally

                                                    E_{1}=1.5\ eV

                                                   

                                                   

6 0
2 years ago
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