Do as physics instructor fred cauthen does and place a tennis ball close to and above the top of a basketball. drop the balls to
1 answer:
Answer:
after shock
creating a system for the conservation of the energy of the basketball ball and creating a system for the tennis ball only, the conservation of energy should be applied to each system independently
Explanation:
When the two balls fall they acquire the same speed since they are accelerated by the same force, their weight and the acceleration of the acceleration of gravity. When reaching the floor the mechanical energy of the system is conserved.
Upon reaching the floor, the first ball (basketball) collides with the floor, this process is very fast, at the end of the process the basketball comes out with a velicad up and collides with the much lighter tennis ball that is still descending .
we assume that the shocks are elastic, when solving the momentary and kinetic energy findings, we find the velocities after each shock
In this clash the tennis ball acquires a high kinetic speed with an upward direction that makes a very high height high. Again this shock is very fast and the tennis ball almost does not move.
Here we must separate the system, creating a system for the conservation of the energy of the basketball ball and another system for the tennis ball only, the conservation of energy should be applied to each system independently
Em₀ =K = 1/2 m v²
= U = m g h
As in the elastic shock the final speed of the tennis ball is approximately 2 vo, we can calculate the maximum height
m g h = 1/2 m (2v₀)²
h = 2 v₀²/g
To reconcile this with the conservation of energy we must calculate the energy for the tennis ball at two points, the first when the crash with the tennis ball ends and at the end point at its maximum height.
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Answer:Thus, The magnetic field around a current-carrying wire is <u><em>directly</em></u> proportional to the current and <u><em>inversely</em></u> proportional to the distance from the wire. If the current triples while the distance doubles, the strength of the magnetic field increases by <u><em>one and half (1.5)</em></u> times.
Explanation:
Magnetic field around a long current carrying wire is given by
where B= magnetic field
permeability of free space
I= current in the long wire and
r= distance from the current carrying wire
Thus, The magnetic field around a current-carrying wire is <u><em>directly</em></u> proportional to the current and <u><em>inversely</em></u> proportional to the distance from the wire.
Now if I'=3I and r'=2r then magnetic field B' is given by
Thus If the current triples while the distance doubles, the strength of the magnetic field increases by <u><em>one and half (1.5)</em></u> times.
Answer:
1)H=714 Watts of energy is given out.
2)614.34 KCal energy is burnt in an hour in the room
3)In freezing conditions, 1337.09 KCal is spent in an hour.
Explanation:
The formula for thermal conductivity states that the rate of heat loss H is as follows:
H= where,
K=Coefficient of thermal conductivity
A=Area of Cross Section
H=Rate of heat loss
x=Thickness of the material
=Temperature difference between the two surfaces of the body in context
=37°C ie. Body Temperature
=20°C ie. Room Temperature
For first case, =17°C or 17°F
K for fat= 0.21
A=2
x=0.01 m
H=
H=714 Watts of energy is given out.
2) ×
Energy= 714 × 60 × 60=2570400 J
2570400 J=614.3403442 KCal
Therefore, 614.3403442 KCal energy is burnt in an hour.
3) Only the temperature difference becomes 37°C from 17°C , rest everything remains the same, therefore the energy will also vary due to the temperature factor and more energy will be spent as in freezing climate °C
E==1337.09 KCal
In freezing conditions, 1337.09 KCal is spent in an hour.