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Elden [556K]
2 years ago
13

Suppose you have two 100 mL graduated cylinders. In each cylinder, there is 37.0 mL of water. You also have two cubes: one is le

ad, and the other is aluminum. The density of lead and aluminum are 11.3 g/mL and 2.70 g/mL respectively. Each cube measures 3.0 cm on each side. After you carefully lower each cube into the water of its own cylinder, what will the new water level be in each of the cylinders? Express your answer to three significant figures and include the appropriate units.
Chemistry
1 answer:
coldgirl [10]2 years ago
7 0

Explanation:

It is known that 1 cm^{3} is equal to 1 ml. And, volume of water in graduate cylinder (V_{w}) is 37.0 ml.

Dimension of cube, a = 3.0 cm

Hence, volume of cube, V_{c} = a^{3} = (3.0 cm)^{3}

                                          = 27 cm^{3}

So,       27 cm^{3} \times \frac{1 ml}{1 cm^{3}}

                          = 27 ml

Initially, it is given that volume of water in both the graduate cylinders is 37.0 ml. So, when cube is lower into the graduate cylinder then volume of water displaced by the cube will raise the height of water level in the graduate cylinder.

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Determine whether the statement is true or false, and why? “Climate change could cause many habitats to be destroyed, leading to
77julia77 [94]

Answer:

False. It should read that both plant and animal species are in danger of extinction, and climate change can destroy habitats.

Explanation:

8 0
2 years ago
What is the concentration of x2??? in a 0.150 m solution of the diprotic acid h2x? for h2x, ka1=4.5??10???6 and ka2=1.2??10???11
lutik1710 [3]
The first dissociation for H2X:
                        H2X +H2O ↔ HX + H3O
initial                0.15                     0      0
change             -X                     +X      +X
at equlibrium 0.15-X                  X        X
because Ka1 is small we can assume neglect x in H2X concentration
     Ka1      = [HX][H3O]/[H2X]
4.5x10^-6 =( X )(X) / (0.15)
X = √(4.5x10^-6*0.15) 
∴X = 8.2 x 10-4 m
∴[HX] & [H3O] = 8.2x10^-4
the second dissociation of H2X
        HX + H2O↔ X^2 + H3O
    8.2x10^-4          Y         8.2x10^-4
Ka2 for Hx = 1.2x10^-11
Ka2       = [X2][H3O]/[HX]
1.2x10^-11= y (8.2x10^-4)*(8.2x10^-4)
∴y = 1.78x10^-5
∴[X^2] = 1.78x10^-5 m


4 0
2 years ago
which diagram best illustrates the ion-molecule attractions that occur when the ions of NaCl(s) are added to water
tatuchka [14]
Diagram is on the picture below.
Answer is: 1).
Sodium chloride is ionic compound and in the water dissociate in sodium cation (positive charge) and chloride anion (negative charge). Water is polar compound, oxagan has negative charge and hydrogen charge. Positive interact witn negative charge and negative with positive charge.

8 0
2 years ago
Suppose a soap manufacturer starts with a triglyceride that has the fatty acid chains arachidic acid, palmitic acid and palmitic
DIA [1.3K]

Answer:

Sodium arachidate; Sodium palmitate and Sodium palmitate

Explanation:

Triglycerides are esters of fatty acids with glycerol. In triglycerides, three fatty acid molecules are linked by ester bonds to each of the three carbon atoms in a glycerol molecule. The fatty acids may be same or different fatty acid molecules. Hydrolysis of triglycerides yields the three fatty acid molecules and glycerol.

Saponification is the process by which a base is used to catalyst the hydrolysis of the ester bonds in glycerides. The products of this base-catalyzed hydrolysis of triglycerides are the metallic salts of the three fatty acids and glycerol. The salts of the fatty acids are known as soaps.

For a triglyceride that has the fatty acid chains arachidic acid, palmitic acid and palmitic acid attached to the three backbone carbons glycerol, the saponification of the triglyceride with NaOH will yield the sodium salts or soaps of the three fatty acids as well as glycerol.

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The two palmitic acid molecules will each react with NaOH to yield sodium palmitate.

8 0
1 year ago
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GuDViN [60]

Answer:  A) Bent or angular, polar

Explanation:

The central atom oxygen has two lone pairs and two bond pairs in OF_2. The number of electron pairs are 4,  that means the hybridization will be sp^3 and the electronic geometry of the molecule will be tetrahedral. But as there are two lone pair of atoms around the central oxygen atom, repulsion between lone and bond pair of electrons is more and hence the molecular geometry will be bent shape.

The compound OF_2 is polar as the net dipole moment of oxygen - fluoride bonds do not cancel each other out.

3 0
1 year ago
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