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scoundrel [369]

2 years ago

9

A 9000-N automobile is pushed along a level road by four studentswho apply a total forwardforce of 500 N. Neglecting friction, t

he acceleration of theautomobile is:
A. 0.055m/s2B. 0.54m/s2C. 1.8m/s2D. 9.8m/s2E. 18m/s2

1 answer:

Anna71 [15]2 years ago

5 0

Answer:

B. 0.54 m/s²

Explanation:

Acceleration: This can be defined as the rate of change of velocity. The S.I unit of acceleration is m/s².

From Newton's fundamental equation,

F = ma .................. Equation 1

Where F = force applied on the automobile, m = mass of the automobile, a = acceleration of the automobile.

Making a the subject of the equation,

a = F/m .................. Equation 2

But,

W = mg................... Equation 3

Where W = weight of the automobile, g = acceleration due to gravity.

Given: W = 9000 N, g = 9.8 m/s²

Substitute into equation 3

9000 = 9.81m

m = 9000/9.81

m = 917.43 kg.

Also given: F = 500 N. and m = 917.43 kg

Substitute into equation 2,

a = 500/917.43

a = 0.54 m/s²

Hence the acceleration of the automobile = 0.54 m/s²

The right option is B. 0.54 m/s²

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