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mafiozo [28]
2 years ago
14

(a) Write the reaction for the overall oxidation of propane (C3H8) with oxygen to produce CO2 and water.

Chemistry
1 answer:
Pavlova-9 [17]2 years ago
4 0

Answer:

Oxidation is the loss of electrons, that is, addition of electronegetive elements, example is addition of oxygen. Also, removal of electropositive elements, example is removal of hydrogen.

Explanation: a) In the presence of excess oxygen, propane burns in air, which gives the following chemical equation:

C3H8 + 5O2⇒ 3CO2 + 4H2O +Heat

b) When insufficient oxygen or too much oxygen is present for complete combustion, the following equation is given:

2C3H8 + 9O2 ⇒ 4CO2 + 2CO + 8H2O + Heat

c) At the anode( negative terminal): O∧2- ⇒ O + e

Oxygen accepts electron.

d) At cathode ( positive terminal): H∧+ + e∧- ⇒ H

Hydrogen donates electron

d) Nernst equation for reversal potential is given as follows:

E= RT/zF  In{ion outside cell}/{ion inside cell}= 2.303 RT/zF In{ion outside cell}/{ion inside cell}

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Explanation:

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The crystalline hydrate cd(no3)2 ⋅ 4h2o(s) loses water when placed in a large, closed, dry vessel at room temperature: cd(no3)2⋅
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8 0
2 years ago
Read 2 more answers
What is the specific heat of an unknown substance if a 2.50 g sample releases 12 calories as its
pishuonlain [190]

Answer:

c = 4016.64 j/g.°C

Explanation:

Given data:

Mass of substance = 2.50 g

Calories release = 12 cal (12 ×4184 = 50208 j)

Initial temperature = 25°C

Final temperature = 20°C

Specific heat of substance = ?

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Solution:

Q = m.c. ΔT

ΔT  = T2 - T1

ΔT  = 20°C - 25°C

ΔT  = -5°C

50208 j = 2.50 g . c. -5°C

50208 j = -12.5 g.°C .c

50208 j /-12.5 g.°C =  c

c = 4016.64 j/g.°C

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2 years ago
Which electron has a higher probability of being found at 4 Å of the nucleus, one in a 2s orbital or one in a 2p orbital?
Lena [83]

Answer:

one in a 2s orbital

Explanation:

Because of the peak near the nucleus in the 2s curve there is a higher probability of finding a 2s within 4 Å of the nucleus. In a multi-electron atom an electron in a 2s orbital will have a lower energy than one in a 2p orbital

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2 years ago
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