Hello!
A stretched spring has 5184 J of elastic potential energy and a spring constant of 16,200 N/m. What is the displacement of the spring?
0.57 m
0.64 m
0.80 m
1.25 m
Data:



For a spring (or an elastic), the elastic potential energy is calculated by the following expression:

Where k represents the elastic constant of the spring (or elastic) and x the deformation or displacement suffered by the spring.
Solving:









Answer:
The displacement of the spring = 0.8 m (or 0.80 m)
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I Hope this helps, greetings ... Dexteright02! =)
Answer:
a and b.
Explanation:
In general types of wave
1. Transverse wave :
In these waves particle are vibrate perpendicular to motion of waves.
Ex : Electromagnetic wave , Radio wave .
2. Longitudinal wave :
In these waves particle are vibrate along the motion of waves.
Ex : Sound wave
Mechanical wave :
1 .These are transverse wave or Longitudinal wave or combination of them .
2.These waves required medium for propagation.
3. The particle are vibrate perpendicular to motion of waves.
So the option a and b are correct.
Answer:
B). to the right
Explanation:
Since the direction of magnetic field is into the page
So here we know that

now the velocity is from bottom to top
so we have

now the force on the moving charge is given as

now we have


so force will be towards Right
Explanation:
It is given that,
Magnetic field, B = 0.1 T
Acceleration, 
Charge on electron,
Mass of electron,
(a) The force acting on the electron when it is accelerated is, F = ma
The force acting on the electron when it is in magnetic field, 
Here, 
So, 
Where
v is the velocity of the electron
B is the magnetic field


v = 341250 m/s
or

So, the speed of the electron is 
(b) In 1 ns, the speed of the electron remains the same as the force is perpendicular to the cross product of velocity and the magnetic field.
To develop this problem we will apply the concepts related to the Doppler effect. The frequency of sound perceive by observer changes from source emitting the sound. The frequency received by observer
is more than the frequency emitted by the source. The expression to find the frequency received by the person is,

= Frequency of the source
= Speed of sound
= Speed of source
The velocity of the ambulance is


Replacing at the expression to frequency of observer we have,


Therefore the frequency receive by observer is 878Hz