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2 years ago

9

An electric field of 4.0 μV/m is induced at a point 2.0 cm from the axis of a long solenoid (radius = 3.0 cm, 800 turns/m). At w

hat rate is the current in the solenoid changing at this instant?

1 answer:

vagabundo [1.1K]2 years ago

6 0

Answer:

The rate of current in the solenoid is 0.398 A/s

Explanation:

Given that,

Electric field $E = 4.0\ \mu V/m$

Distance = 2.0 cm

Radius = 3.0 cm

Number of turns per unit length = 800

We need to calculate the rate of current

Using formula of electric field for solenoid

$E = \dfrac{x}{2}\mu_{0}n\dfrac{dI}{dt}$

Where, x = distance

n = number of turns per unit length

E = electric field

r = radius

Put the value into the formula

$4.0\times10^{-6}=\dfrac{2.0\times10^{-2}}{2}\times4\pi\times10^{-7}\times800\times\dfrac{dI}{dt}$

$\dfrac{dI}{dt}=\dfrac{4.0\times10^{-6}\times2}{2.0\times10^{-2}\times4\pi\times10^{-7}\times800}$

$\dfrac{dI}{dt}=0.397\ A/s$

Hence, The rate of current in the solenoid is 0.398 A/s.

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Answer:

$v_e=\sqrt{\frac{m_pv_p^2}{m_e}}$

Explanation:

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by using the Newton second law for the proton, and by using kinematic equation for the calculation of the acceleration you can obtain:

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(it has been used that vp^2 = v_o^2+2ad) where d is the separation of the plates, ap the acceleration of the proton, vp its velocity and mp its mass.

By doing the same for the electron you obtain:

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we can equals these expressions for both proton and electron, because the forces qE are the same:

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Answer:

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Reaction time of an alert driver = 3 sec

extra time taken by sleepy driver over an alert driver = 3 - 0.8 = 2.2 sec

now, extra distance that car will travel in case of sleepy driver will be'

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S_d = 33.3333 m/s × 2.2 sec

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2 years ago

Two weights are connected by a very light cord that passes over an 80.0Nfrictionless pulley of radius 0.300m. The pulley is a so

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Answer:

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Adding the two equations:

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$\tau =r(T_{2} -T_{1} )$

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$a=\frac{g*(W_{2}-W_{1})}{W_{1}+W_{2} +\frac{W}{2} }$

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2 years ago

Determine the scalar components Ra and Rb of the force R along the nonrectangular axes a and b. Also determine the orthogonal pr

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Answer: Hello your question is incomplete attached below is the complete question

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2 years ago