A 2.80 kg mass is dropped from a height of 4.50 m. find its potential energy(PE) at the moment it is dropped. PLEASE HELP
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Answer:
The speed of the cat when it hits the ground is approximately 7.586 meters per second.
Explanation:
By Principle of Energy Conservation and Work-Energy Theorem, we have that initial potential gravitational energy of the cat (), in joules, is equal to the sum of the final translational kinetic energy (
), in joules, and work losses due to air resistance (
), in joules:
(1)
By definition of potential gravitational energy, translational kinetic energy and work, we expand the equation presented above:
(2)
Where:
- Mass of the cat, in kilograms.
- Gravitational acceleration, in meters per square second.
- Initial height of the cat, in meters.
- Final speed of the cat, in meters per second.
If we know that ,
,
and
, then the final speed of the cat is:
The speed of the cat when it hits the ground is approximately 7.586 meters per second.