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2 years ago

Discuss the three broad areas of Financial Decision Making

1 answer:

3 0

Three broad areas of financial decision making are capital budgeting, capital structure and working capital management. Capital budgeting The first and most important decision that any firm has to make is to define the business or business that it wants to be in. this is reffered to as strategic planning and it has a significant bearing on how capital is allocated in the firm. As strategic planning calls for evaluating costs and benefits spread out over time, it is essentially a financial decision process. Capital structure Once a firm has decided on the investment projects it want to undertake, it has to figure out ways and means of financing them. The key issues in capital structure decision are: what is the optimal...

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X-rays have a wavelength small enough to image individual atoms, but are challenging to detect because of their typical frequenc

Cerrena [4.2K]

Explanation:

Given: $\lambda = 8.38\:\text{nm} = 8.38×10^{-9}\:\text{m}$

Its frequency $\nu$ is defined as

$\nu = \dfrac{c}{\lambda} = \dfrac{3×10^8\:\text{m/s}}{8.38×10^{-9}\:\text{m}}$

$\:\:\:\:= 3.58×10^{16}\:\text{Hz}$

7 0

1 year ago

The transition metal with the smallest atomic mass

solniwko [45]

The transition metal with the smallest atomic mass is Scandium (Sc).
Hope this helps~

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2 years ago

For a school event 1/6 of the athletic field is reversed for the fifth -grade classes the reserved part of the field is divided

SVETLANKA909090 [29]

Answer:

$\frac{1}{24}$

Explanation:

Given:

For a school event, 1/6 of the athletic field is reserved for the fifth -grade classes and the reserved part of the field is divided equally among the 4 fifth grade classes in the school.

To find: fraction of the whole athletic field reserved for each fifth class

Solution:

Fraction of the whole athletic field reserved for four fifth classes = $\frac{1}{6}$

So, fraction of the whole athletic field reserved for each fifth class = $\frac{1}{4}(\frac{1}{6})=\frac{1}{24}$

3 0

2 years ago

What is the sequence of energy transformations that occur in a nuclear reactor? nuclear energy Right arrow. Mechanical energy Ri

Mademuasel [1]

Answer:

NUCLEAR ENERGY -----> MECHANICAL ENERGY -------> THERMAL ENERGY --------> ELECTRICAL ENERGY

Explanation:

In nuclear reactor, various energy transformations occur in order to generate electricity. Nuclear reactor converts the energy released from nuclear fission and the heat generated is removed from the reactor by a cooling system where steam is generated. The steam then drives a turbine which powers a generator to produce electricity.

A nuclear reactor is hence an equipment where nuclear chain reactions occur and control can be obtained. The nuclear reactor uses mostly uranium-235 and Plutonium-239. When these radioactive substances absorbs neutrons, they undergo nuclear fission causing the nucleus to split into two or more smaller compounds with the release of kinetic energy a form of mechanical energy, gamma radiations and others.The kinetic energy is then harnessed in the equipment as heat (thermal energy) which is received by a cooling system and steam is generated. The steam can then power the generator from which electricity is obtained (electrical energy).

So therefore, in a nuclear reactor, the nuclear energy is transformed to mechanical energy and then thermal energy which powers the generation of the electrical energy.

6 0

2 years ago

What is the final pressure (expressed in atm) of a 3.05 l system initially at 724 mm hg and 298 k, that is compressed to a final

krok68 [10]

Answer:

P2 = 778.05 mm Hg = 1.02 atm

Explanation:

We are to find the final pressure (expressed in atm) of a 3.05 liter system initially at 724 mm hg and 298 K which is compressed to a final volume of 2.60 liter at 273 K.

For this, we would use the equation:

$\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}$

where P1 = 724 mm hg

V1 = 3.05 L

T1 = 298 K

P2 = ?

V2 = 2.6 L

T2 = 173 K

Substituting the given values in the equation to get:

$\frac{(724)(3.05)}{298} =\frac{P_2(2.6)}{173}$

P2 = 778.05 mm Hg = 1.02 atm

7 0

2 years ago