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2 years ago

Nathan accelerates his skateboard uniformly along a straight path from rest to 12.5 m/s in 2.5 s.

Physics

1 answer:

kicyunya [14]2 years ago

5 0

Answer:

<h2>a) Nathan's acceleration is 5 m/s² </h2><h2>b) Nathan's displacement during this time interval is 15.625 m</h2><h2>c) Nathan's average velocity during this time interval is 6.25 m/s</h2>

Explanation:

a) We have equation of motion v = u + at

Initial velocity, u = 0 m/s

Final velocity, v = 12.5 m/s

Time, t = 2.5 s

Substituting

v = u + at

1.25 = 0 + a x 2.5

a = 5 m/s²

Nathan's acceleration is 5 m/s²

b) We have equation of motion s = ut + 0.5 at²

Initial velocity, u = 0 m/s

Acceleration, a = 5 m/s²

Time, t = 2.5 s

Substituting

s = ut + 0.5 at²

s = 0 x 2.5 + 0.5 x 5 x 2.5²

s = 15.625 m

Nathan's displacement during this time interval is 15.625 m

c) Displacement = 15.625 m

Time = 2.5 s

We have

Displacement = Time x Average velocity

15.625 = 2.5 x Average velocity

Average velocity = 6.25 m/s

Nathan's average velocity during this time interval is 6.25 m/s

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4. A cylindrical tube has a length of 14.4cm and a radius of 1.5cm and is filled with a colorless gas. If the density of the gas

professor190 [17]

Answer:

Mass, m of gas is 0.2504 grams.

Explanation:

First, we need to solve for the volume of the cylindrical tube.

Volume of cylinder is given by the formula;

$V = 2\Pi r^{2}h$

Where, V represents volume.

π represents pie

r represents radius.

h represents height or length.

Given the following data;

Radius, r = 1.5cm

Length, h = 14.4cm

Density, d = 0.00123g/cm³

Substituting into the equation;

$V = 2 * 3.142 * (1.5)^{2}14.4$

$V = 2 * 3.142 * 2.25 * 14.4$

$V = 203. 6016$

Therefore, the volume of the cylindrical tube is 203. 6016cm³

Density can be defined as mass all over the volume of an object.

Simply stated, density is mass per unit volume of an object.

Mathematically, density is given by the formula;

$Density = \frac{mass}{volume}$

$Mass = density * volume$

Substituting into the equation, we have;

$Mass = 0.00123 * 203. 6016$

Mass = 0.2504g.

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2 years ago

A pair of glasses is dropped from the top of a 32.0m stadium. A pen is dropped 2.Os later. How high above the ground is the pen

Svetllana [295]

Answer:

$h_p = 30.46\ m$

Explanation:

<u>Free Fall Motion</u>

A free-falling object refers to an object that is falling under the sole influence of gravity. If the object is dropped from a certain height h, it moves downwards until it reaches ground level.

The speed vf of the object when a time t has passed is given by:

$v_f=g\cdot t$

Where $g = 9.8 m/s^2$

Similarly, the distance y the object has traveled is calculated as follows:

$\displaystyle y=\frac{g\cdot t^2}{2}$

If we know the height h from which the object was dropped, we can solve the above equation for t:

$\displaystyle t=\sqrt{\frac{2\cdot y}{g}}$

The stadium is h=32 m high. A pair of glasses is dropped from the top and reaches the ground at a time:

$\displaystyle t_1=\sqrt{\frac{2\cdot 32}{9.8}}=2.56\ sec$

The pen is dropped 2 seconds after the glasses. When the glasses hit the ground, the pen has been falling for:

$t_2=2.56 - 2 = 0.56\ sec$

Therefore, it has traveled down a distance:

$\displaystyle y=\frac{9.8\cdot 0.56^2}{2} = 1.54\ m$

Thus, the height of the pen is:

$h_p = 32 - 1.54\Rightarrow h_p=30.46\ m$

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A person on a cruise ship is doing laps on the promenade deck. on one portion of the track the person is moving north with a spe

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