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V125BC [204]
2 years ago
8

A vendor buys milk at a certain price, adds water and sells the adulterated milk at the same rate as he bought it for. He makes

a 30% profit. What is the percentage of water that he adds to milk?
Options:
A) 30%
B) 15%
C) 20%
D) 60%
Mathematics
1 answer:
SOVA2 [1]2 years ago
8 0
The correct option is A): "30%" because<span> suppose vendor bought 100 ltr milk at 10/ltr so cost price =1000 rs.
In that he adds "x" ltr of water in order to get profit of 30% above cost price , means his total earnings from adulturated solution will be 1300 rs.</span>
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A boxer weighs 14 stone 5 lbs. To be in the heavyweight division, he must be &gt; 91 kg. What is his weight in kg to 2 decimal p
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14x14= 196 lb.
196/2.2= 89.09 kg.

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4 0
2 years ago
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Explain the steps for dividing decimals. Write three or four sentences.
SVETLANKA909090 [29]

Answer:

Step-by-step explanation:

Move the decimal point in the divisor and dividend.

Turn the divisor (the number you’re dividing by) into a whole number by moving the decimal point all the way to the right. At the same time, move the decimal point in the dividend (the number you’re dividing) the same number of places to the right.

Place a decimal point in the quotient (the answer) directly above where the decimal point now appears in the dividend.

Divide as usual, being careful to line up the quotient properly so that the decimal point falls into place.

Line up each digit in the quotient just over the last digit in the dividend used in that cycle.

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2 years ago
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A survey on healthy choices was given to gym members at Work It Out. The results
irina [24]

Answer:

The correct option is 4) 0.72.

Step-by-step explanation:

Consider the provided information.

Let us consider that there are 100 members.

(Note: you can take any number the answer will remain the same.)

90% of its members drank protein shakes and of the members who drank  protein shakes.

90% of 100 is 90.

Thus, 90 members drank protein shake.

Of the members who drank   protein shakes, 30% took weight-loss medication.

30% of 90 is 27.

That means 27 out of 90 took weight loss medication.

Out of 100 members 90 drank protein shakes that means 10 members does not take protein shakes.

Only 10% of members  who did not drink protein shakes took weight-loss medication.

10% of 10 is 1, that means 1 member out of 10 took weight loss medication.

Thus the required table is:

                                        Medication   Not Medication      Total

Drank shakes                       27                   63                      90

Doesn't Drank shakes          1                      9                        10

Total                                      28                   72                     100

Now we need to find the probability that a gym member does not take weight-loss medication.

72 out of 100 members does not take weight-loss medication.

Therefore, the required probability is: \frac{72}{100}=0.72

Hence, the correct option is 4) 0.72.

5 0
2 years ago
In the function y = 0.25x + 3.5, y represents the cost of a gallon of milk after a certain number of years, x. How much does the
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4 0
2 years ago
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Test the given claim. Identify the null​ hypothesis, alternative​ hypothesis, test​ statistic, P-value, and then state the concl
never [62]

Answer:

a) Failed to reject the null hypothesis (P-value=0.09).

b) The 95% CI for the difference in proportions is:

-0.0599\leq\pi_1-\pi_2\leq0.0124

Step-by-step explanation:

a) We have to perform a hypothesis test for the difference of proportions.

The null and alternative hypothesis are:

H_0: \pi_1\geq\pi_2\\\\H_1: \pi_1

The significance level is 0.05.

The proportion of the passenger cars owners is:

p_1=\frac{239}{2142} =0.1116

The proportion of commercial truck owners is:

p_2=\frac{54}{399}=0.1353

The weigthed average p is

p=\frac{n_1p_1+n_2p_2}{n_1+n_2}=\frac{239+54}{2142+399}=0.1153

The estimated standard deviation is

s=\sqrt{\frac{p(1-p)}{n_1}+\frac{p(1-p)}{n_2}} =\sqrt{\frac{0.1153(1-0.1153)}{2142}+\frac{0.1153(1-0.1153)}{399}} =0.0174

We can calculate the z-value as:

z=\frac{\Delta p}{s}=\frac{0.1116-0.1353}{0.0174}=-1.362

The P-value for z=-1.362 is P=0.0866.

The P-value (0.09) is greater than the significance level (0.05), so it failed to reject the null hypothesis. There is no enough evidence to prove that commercial trucks owners violate laws requiring front license plates at a higher rate than owners of passenger cars.

b) We can construct a 95% CI, according to the significance level of 0.05.

The z-value for this CI is 1.96.

We have to recalculate the standard deviation:

\sigma=\sqrt{\frac{p_1(1-p_1)}{n_1} +\frac{p_2(1-p_2)}{n_2}} =\sqrt{\frac{0.1116(1-0.1116)}{2142} +\frac{0.1353(1-0.1353)}{399}} =0.0184

The lower limit is then:

LL=(p_1-p_2)-z*\sigma=(0.1116-0.1353)-1.96*0.0184=-0.0238-0.0361\\\\LL=-0.0599

The upper limit is:

UL=(p_1-p_2)+z*\sigma=(0.1116-0.1353)+1.96*0.0184=-0.0238+0.0361\\\\UL=0.0124

The 95% CI for the difference in proportions is:

-0.0599\leq\pi_1-\pi_2\leq0.0124

In this case, we can conclude that the difference between the proportions, with 95% confidence, can still be equal or greater than zero, meaning that it is possible passenger car owners violate laws more than truck owners.

7 0
2 years ago
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