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amid [387]
2 years ago
9

The speed of sound in fresh water at 293k is 1482 m/s. At what temperature is the speed of sound in helium gas the same as that

of fresh water at 293k? Helium is considered a monatomic ideal gas (y = 1.67 and atomic mass = 4.003u).
A)442K
B)377K
C)525K
D)313K
E)633K
Physics
1 answer:
USPshnik [31]2 years ago
3 0
<span>The speed of sound in fresh water at 293k is 1482 m/s.
</span><span>At 633K temperature is the speed of sound in helium gas the same as that of fresh water at 293k.
</span><span>E)633K</span>
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The Newton’s law Nikolas would use to come up with this idea is the <span>Third law that states:

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1. Suppose a tank filled with water has a liquid column with a height of 10 meters. If the area is 2 square meters (m²), what's
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Answers:


1. Firstly, we have to define that Pressure P is Force applied F per unit area A. It is mathematically expressed as follows:


P=\frac{F}{A}   (1)


The unit of P is Pascal (Pa) which is equivalent to \frac{kg}{ms^{2}} and also equivalent to \frac{N}{m^{2} }


There is also another expression of the Pressure in which it is dependent on the density d  of the liquid, the height h of the container and the gravity force g:


P=d*h*g     (2)


In this problem the liquid is water, and its known density is approximately:


d=1000kg/m^{3}


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P=1000\frac{kg}{m^{3}}*10m*9.8\frac{m}{s^{2}}


P=98000Pa


Then, we have to substitute this value in equation (1) and clear F:


F=P*A


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F=196000N



2. For this problem, we will use equation (1) to find the Pressure. We already know the area A and the force exerted by water in the container F:


P=\frac{F}{A}=\frac{900N}{3m^{2}}


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3. In this case, equation (2) is the perfect way to find the hydrostatic pressure at any point at the bottom of the tank <u>(be careful with the units):</u>


P=d*h*g      

P=1000\frac{kg}{m^{3}}*7.5m*9.8\frac{m}{s^{2}}      


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P_{2}- P_{1} =d*g(h_{2}- h_{1})   (3)


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P_{2}-1500Pa=1000\frac{kg}{m^{3}}*9.8\frac{m}{s^{2}} (6m-2m)    


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P=\frac{F}{A}


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Answer:

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