answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Levart [38]
2 years ago
8

Thirty grams of lead oxide and fifteen grams of ammonia react completely to produce solid lead, nitrogen gas, and liquid water.

What will be approximate mass of all three products? 10 g 15 g 45 g 450 g
Chemistry
2 answers:
Kitty [74]2 years ago
8 0

45 g  Thirty grams of lead oxide and fifteen grams of ammonia react completely to produce solid lead, nitrogen gas, and liquid water.

nasty-shy [4]2 years ago
7 0

<u>Answer:</u> The approximate mass of three products are 45g.

<u>Explanation:</u>

Law of Conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another. Total mass on the reactant side is always equal to the total mass on the product side.

This law is followed by all the balanced chemical equations.

For the reaction of lead oxide and ammonia, the equation follows:

3PbO(s)+2NH_3(aq.)\rightarrow 3Pb(s)+N_2(g)+3H_2O(l)

Total mass on the reactant side = Mass of PbO + Mass of NH_3 = (30 + 15) = 45 g

As, this is a balanced chemical equation and hence, will follow law of conservation of mass. So,

Total mass of the products = Total mass of the reactants = 45 g

Therefore, the approximate mass of three products are 45g.

You might be interested in
How many molecules of glucose are in 1 l of a 100 mm glucose solution?
Karolina [17]

Answer is: 6.022·10²² molecules of glucose.

c(glucose) = 100 mM.

c(glucose) = 100 · 10⁻³ mol/L.

c(glucose) = 0.1 mol/L; concentration of glucose solution.

V(glucose) = 1 L; volume of glucose solution.

n(glucose) = c(glucose) · V(glucose).

n(glucose) = 0.1 mol/L · 1 L.

n(glucose) = 0.1 mol; amount of substance.

N(glucose) = n(glucose) · Na (Avogadro constant).

N(glucose) = 0.1 mol · 6.022·10²³ 1/mol.

N(glucose) = 6.022·10²².

6 0
2 years ago
Simplify: <br>(100 m)/(26 s)
podryga [215]

100m/26s=50m/13s

50m/13s=3.846m/s

4 0
2 years ago
Read 2 more answers
If you perform the experiment described in investigation #15 by mixing 10 g of glue with 13 g of water and 8 g of sodium borate
Phantasy [73]

10 g of glue with 13 g of water ,

Mass ratio of the material can be calculated as:    

\frac{Mass of glue}{Mass of glue + Mass of water}  

\frac{10 g}{10 g + 13 g }  

\frac{10 g}{23 g }

8 g of sodium borate suspended in 11 g of water, mass ratio can be calculated as:

\frac{Mass of sodium borate}{Mass of sodium borate + Mass of water}  

\frac{ 8 g}{ 8 g + 11 g }  

\frac{8 g}{19 g }

3 0
2 years ago
When monomers combine to form a condensation polymer, another product is also formed. typically, this product is _____. methanol
shtirl [24]
Water is the answer!
4 0
2 years ago
Read 2 more answers
A 40.0 mL sample of 0.25 M KOH is added to 60.0 mL of 0.15 M Ba(OH)2. What is the molar concentration of OH-(aq) in the resultin
solmaris [256]

Answer:

C) 0.28 M

Explanation:

Considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Moles =Molarity \times {Volume\ of\ the\ solution}

Potassium hydroxide will furnish hydroxide ions as:

KOH\rightarrow K^{+}+OH^-

Given :

<u>For Potassium hydroxide : </u>

Molarity = 0.25 M

Volume = 40.0 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 40.0×10⁻³ L

Thus, moles of hydroxide ions furnished by Potassium hydroxide is same as the moles of Potassium hydroxide as shown below:

Moles =0.25 \times {40.0\times 10^{-3}}\ moles

Moles of hydroxide ions by Potassium hydroxide = 0.01 moles

Barium hydroxide will furnish hydroxide ions as:

Ba(OH)_2\rightarrow Ba^{2+}+2OH^-

Given :

<u>For Barium hydroxide : </u>

Molarity = 0.15 M

Volume = 60.0 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 60.0×10⁻³ L

Thus, moles of hydroxide ions furnished by Barium hydroxide is twice the moles of Barium hydroxide as shown below:

Moles =2\times 0.15 \times {60.0\times 10^{-3}}\ moles

Moles of hydroxide ions by Barium hydroxide = 0.018 moles

Total moles = 0.01 moles + 0.018 moles = 0.028 moles

Total volume = 40.0×10⁻³ L + 60.0×10⁻³ L = 100×10⁻³ L

Concentration of hydroxide ions is:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity_{OH^-}=\frac{0.028 }{100\times 10^{-3}}

<u> The final concentration of hydroxide ion = 0.28 M</u>

5 0
2 years ago
Read 2 more answers
Other questions:
  • What is the molarity of 4.35 moles kmno4 dissolved in 750 ml of solution?
    15·1 answer
  • Which nuclear emission moving through an electric field would be deflected toward the positive electrode?
    5·1 answer
  • How many grams are in 1.183 mol of carbon dioxide (CO2) gas?
    7·2 answers
  • A radioisotope is placed near a radiation detector, which registers 64 counts per second. Eight hours later, the detector regist
    11·2 answers
  • A man pours some hot coffee into a small cup from a large jug that contains enough coffee for several cups. Which statement corr
    14·2 answers
  • At 298 K and 1 atm, bromine is a liquid with a high vapor pressure, whereas chlorine is a gas. This provides evidence that, unde
    13·1 answer
  • The infrared spectrum above represents the absorption of certain wavelengths of radiation by molecules of CO2. Which of the foll
    9·1 answer
  • Which is an example of how society affects science?
    9·2 answers
  • How do acids and bases affect molecules such Proteins? ​
    15·1 answer
  • A slug takes 4.25 minutes to travel 11.2 centimeters. What is the speed of the slug in minutes per second?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!