it could be either o,3.5 or 80,50
- <em>it also could be both, maybe</em>
<span>a^3 - b^3 = (a - b) </span><span>(<span>a^2 + </span>ab + b^2)
</span><span>so
x^3 - 4^3 = (x - 4)(x^2 + 4x + 16)
hope it helps</span>
Here are your measures of variability. The range is found by subtracting the highest and the lowest (29-5=24). To find the interquartile range, you will find the median of the lower half of the data and the median of the higher half of sta and subtract these 2 numbers. Here is your list. I have PUT PARENTHESES around the upper and lower quartiles: 5, 17, (18), 20, 20, 21, 23, (26), 28, 29. It is like finding the middle of the entire set of data and then finding the middle of each half. Subtract 26 and 18 to find the interquartile range of 8 touchdowns.
The value of x = 24
Step-by-step explanation:
The proportion is set as ;

Applying cross product
9*16=6*x
144=6x --------simplify by dividing by 6 both sides
144/6 = 6x/6
24=x
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Proportion in Enlargement : brainly.com/question/9930004
Keywords : proportion, enlargement ,triangles, cross products
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The angle whose sine is 0.39581 is 23.31650126° (round it how you want).
To calculate this, you need to do the inverse sine of 0.39581.
Inverse sine looks like

, however, it is not the sine of the angle to the power of -1.