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VashaNatasha [74]
2 years ago
3

When two unlike air masses meet what usually keeps them separate

Physics
1 answer:
slava [35]2 years ago
3 0

Answer:

When two unlike air masses meet what usually keeps them separate

The answer is "difference in density"

Explanation:

Air mass means a large mass of air that can be characterized by their temperature and humidity within it. Air mass picks up the distinct temperature and humidity characteristics of a region when it sits over that region for several days, or longer, and, this occur when it is slowly pushed along by high-level winds. In other words, Air masses build when the air stagnates over a region for several days/weeks.

Air masses that are formed when the atmosphere remains in contact with a large, relatively uniform land or sea surface for a time can be classified according to the temperature and moisture characteristics where they develop. Heat is brought to cold areas and cools down areas that are warm because, cold air masses tend to flow toward the equator and warm air masses tend to flow toward the poles.

When two large air masses meet, the boundary that separates them is called a front, and the properties of air masses are determined by the the underlying surface properties where they originate. As an air mass moves, it tends to retain the properties of the region where it formed and when different air masses meet, they don't mix. Cold air masses are denser and sink, while warm air masses are less dense and rise, which makes more clouds form, which brings precipitation when warm air rises. There are four different boundary between two air masses- Cold, Warm, Stationary, and Occluded. Cold boundary forms when a cold air mass pushes under a warm air mass, forcing the warm air to rise. While, warm boundary forms when a moist, warm air mass slides up and over a cold air mass.

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Fiber optic (FO) cables are based upon the concept of total internal reflection (TIR), which is achieved when the FO core and cl
kozerog [31]

Answer:

False

Explanation:

Though fiber active cable is based on the concept of internal reflection but it is achieved by refractive index which transmit data through fast traveling pulses of light. It has a layer of glass and insulating casing called “cladding,”and this is is wrapped around the central fiber thereby causing light to continuously bounce back from the walls of the Cable.

7 0
2 years ago
1) A sound wave with a frequency of 300 hertz is traveling through a medium at a speed of 320 meters/second. What is its wavelen
timurjin [86]
1. The wavelength is the ratio of the wave's speed to its frequency in hertz or 1/s. This is shown below,
                           λ = s / f = (320 m/s)  / (300 1/s) = 1.07 m
The wavelength is approximately 1.07 m.

2. The frequency is the ratio between speed and the wavelength,
                        f = (330 m/s) / 0.45 m = 733.33 hertz

 
5 0
2 years ago
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A device that uses electricity and magnetism to create motion is called a (motor magnet generator) . In a reverse process, a dev
Tems11 [23]

the answers are a. and c.

I hope I help you out!

6 0
2 years ago
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(1) A typical person has a surface area of about 2m^2 and a layer of fat about 1cm thick (It can vary from 0.5 cm to 1.5 cm) . E
KATRIN_1 [288]

Answer:

1)H=714 Watts of energy is given out.

2)614.34 KCal energy is burnt in an hour in the room

3)In freezing conditions, 1337.09 KCal is spent in an hour.

Explanation:

The formula for thermal conductivity states that the rate of heat loss H is as follows:

H=\frac{KA (T_{1}-T_{2})}{x}   where,

K=Coefficient of thermal conductivity

A=Area of Cross Section

H=Rate of heat loss

x=Thickness of the material

T_{1}-T_{2}=Temperature difference between the two surfaces of the body in context

T_{1}=37°C ie. Body Temperature

T_{2}=20°C ie. Room Temperature

For first case, T_{1}-T_{2}=17°C or 17°F

K for fat= 0.21 Wm^{-1}K^{-1}

A=2m^{2}

x=0.01 m

H=\frac{0.21 * 2* 17}{0.01}

H=714 Watts of energy is given out.

2) Power×Time(in seconds) = Energy

Energy= 714 × 60 × 60=2570400 J

2570400 J=614.3403442 KCal

Therefore, 614.3403442 KCal energy is burnt in an hour.

3) Only the temperature difference becomes 37°C from 17°C , rest everything remains the same, therefore the energy will also vary due to the temperature factor and more energy will be spent as in freezing climate T_{2}=0 °C

E=\frac{614.34*37}{17}=1337.09 KCal

In freezing conditions, 1337.09 KCal is spent in an hour.

8 0
2 years ago
In which applications are sound waves reflected? Check all that apply.
mojhsa [17]

detecting diseases, locating damaged cells, monitoring fetal development

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