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Vlad1618 [11]
2 years ago
12

The Texas Motor Speedway is an oval racing track with curves of radius 229 m that are banked at an angle of 24.0°. The size of t

he track allows for race cars to achieve speeds in excess of 400 km/h. An unintended consequence of the banked curves and high speeds is that race car drivers experience excessive G forces, especially in the "vertical" direction (with respect to their body position), causing dizziness and loss of consciousness.
(a)A daring driver, pushing his car to the limit, experiences 3.57g of centripetal acceleration during one banking maneuver. What is the speed of his car during the maneuver? (Give your answer in km/h.)
km/h
(b)If the driver is seated so that during the banking maneuver his upper body is aligned with the direction normal to the banked curve, what is the magnitude of the component of the centripetal acceleration along the driver's upper body? (Give your answer in terms of g.)
Physics
1 answer:
kenny6666 [7]2 years ago
5 0

Answer:

Explanation:

Given that the road is banked at an angle of 24.0°

a = 3.57g

but a = v^2/r = centripetal acceleration

v = square root (ar)

radius = 229m

v = square root ( 229 x 3.57g)

= square root (229 x 3.57 x 9.81)

= 89.55m/s x 1km/1000m x 3600s/1hr

= 322.29km/hr

b) component of centripetal acceleration = asinФ

= 3.57g x sin 24.0° = 14.24m/s^2

= 1.45g

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A child is running his 46.1 g toy car down a ramp. The ramp is 1.73 m long and forms a 40.5° angle with the flat ground. How lon
frosja888 [35]

Answer:

t=0.704s

Explanation:

A child is running his 46.1 g toy car down a ramp. The ramp is 1.73 m long and forms a 40.5° angle with the flat ground. How long will it take the car to reach the bottom of the ramp if there is no friction?

from newton equation of motion , we look for the y component of the speed and look for the x component of the speed. we can then find the resultant of the speed

V^{2} =u^{2} +2as

Vy^2=0+2*9.8*1.73sin40.5

Vy^2=22.021

Vy=4.69m/s

Vx^2=u^2+2*9.81*cos40.5

Vy^2=25.81

Vy=5.08m/s

V=(Vy^2+Vx^2)^0.5

V=47.71^0.5

V=6.9m/s

from newtons equation of motion we know that force applied is directly proportional to the rate of change in momentum on a body.

f=force applied

v=velocity final

u=initial velocity

m=mass of the toy, 0.046

f=ma

f=m(v-u)/t

v=u+at

6.9=0+9.8t

t=6.9/9.81

t=0.704s

4 0
2 years ago
After soccer practice, Coach Miller goes to the roof of the school to retrieve the errant soccer balls. The height of the school
blsea [12.9K]
With gravitational acceleration at 9.8, initial height at 3.5m and distance at 22m the initial horizontal velocity is 26.03 ms and the flight time is .845 seconds
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2 years ago
The moon’s orbital speed around Earth is 3.680 × 10^3 km/h. Suppose the moon suffers a perfectly elastic collision with a comet
Naily [24]

Answer:

Speed of comet before collision is

v_{2_{i}}=-2.5\times10^{3}\quad km/h

Explanation:

Correction: (As stated after collision comet moves away from moon so velocity of moon and moon and comet must be opposite in direction. as spped of moon after collision is −4.40 × 10^2km/h so that comet's must be 5.740 × 10^3km/h instead of -5.740 × 10^3km/h)

Solution:

mass \quad of\quad moon = m_{1}\\\\mass\quad of \quad comet = m_{2} = 0.5 m_{1}\\\\speed\quad of\quad moon\quad before\quad collision = v_{1_{i}}=3.680\times 10^3 km/h\\\\speed \quad of\quad moon\quad after\quad collision=v_{1_{f}} = -4.40 \times 10^2 km/h\\\\speed\quad of\quad comet\quad after\quad collision =v_{2_{f}} =5.740 \times 10^3 km/h

Case is considered as partially inelastic collision, by conservation of momentum

m_{1}v_{1_{i}}+m_{2}v_{2_{i}}=m_{1}v_{1_{f}}+m_{2}v_{2_{f}}\\\\m_{1}v_{1_{i}}+0.5m_{1}v_{2_{i}}=m_{1}v_{1_{f}}+0.5m_{1}v_{2_{f}}\\\\v_{1_{i}}+0.5v_{2_{i}}=v_{1_{f}}+0.5v_{2_{f}}\\\\v_{2_{i}}=2(v_{1_{f}}+0.5v_{2_{f}}-v_{1_{i}})\\\\v_{2_{i}}=2(-4.40 \times 10^2+0.5(5.740 \times 10^3)-3.680 \times 10^3 )\\\\v_{2_{i}}=-2.5\times10^{3}\quad km/h

8 0
2 years ago
When particles are connected by a cable, the motions of the particles are _________________. always independent random always de
White raven [17]

Answer:

Option C (always dependent) would be the appropriate answer.

Explanation:

  • The movements including its particles everywhere are depending on when particles were also associated with either a cable, since, if we want the substances to modify their location, one (1).
  • However, if the particles two (2) and then out impact the location of an object two ( 2), they could easily determine the appearance or location.

Some other possible alternatives aren't connected to a particular setting. So, the solution is indeed the right one.

4 0
2 years ago
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