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Nitella [24]
2 years ago
4

Which of the following actions will cause the equilibrium to shift such that the concentration of NO gas will increase? 2NO(g) +

2H2(g) ⇌ N2(g)+2H2O+heat View Available Hint(s) Which of the following actions will cause the equilibrium to shift such that the concentration of gas will increase? Lower the reaction temperature Increase the concentration of H2O(g) Decrease the concentration of N2(g) Increase the concentration of H2(g)
Chemistry
1 answer:
trapecia [35]2 years ago
6 0

Answer:

(b) increase the concentration of H2O

Explanation:

Le Chatelier´s principle will help us to answer this question.

According to this principle if the system is at at equilibrium, any stress or change on it will be responded by the system in such a way as to partilly offset this stress by shifting the equilibrium to attain this equilibria again.

The equilibrium is:

2NO(g) + 2H2(g) ⇌ N2(g)+2H2O+heat

We are interestested in favoring the NO reactant concentration, i.e favor the left side.

(a) Lower the temperature:

the reaction is exothermic, that is liberates heat, so the equilibrium will favor the liberation of heat when the temperature is lowered, so the equilibrium shifts to the right.

(b) Increase the concentration of water gas:

The system will react by consuming partially more water thus shifting the equilibrium towards the left,  increasing the concentration of NO and H2 gas.

(c) Decreasing the concentration of N2 will make the system react towards the producing some N2  to offset the change favoring the right side.

(d) Increasing the concentration of H2 will favor the product side by removing some of the added H2 thus decreasing the concentration of NO.

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Describe the process used to measure out a specific mass of a solid
Svetlanka [38]
Although the process varies slightly from one material to another, the general process is as follows:

1) Choose an appropriate container for the solid. This may be a petri dish or a beaker in which you want to prepare the solution of the solid or any other lab equipment.

2) Place the container on a mass balance, then turn the balance on. The mass balance will automatically zero-out the mass of the container, so that any mass that you add on the container will be the mass of the solid. Alternatively, you may first measure the mass of the empty container alone.

3) Add the solid using a lab spatula. The solid should be added more slowly when the reading on the scale comes close to the desired value.

4) Remove the container from the mass balance after the desired amount of solid has been added.
7 0
2 years ago
If PbI2(s) is dissolved in 1.0MNaI(aq) , is the maximum possible concentration of Pb2+(aq) in the solution greater than, less th
fredd [130]

Answer:

\mathbf{s =\sqrt [3]{\dfrac{K_{sp}}{4}}}

Less than the concentration of Pb2+(aq) in the solution in part ( a )

Explanation:

From the question:

A)

We assume that s to be  the solubility of PbI₂.

The equation of the reaction is given as :

PbI₂(s) ⇌ Pb²⁺(aq) + 2I⁻(aq); Ksp = 7 × 10⁻⁹

 [Pb²⁺] =   s

Then [I⁻] = 2s

K_{sp} =\text{[Pb$^{2+}$][I$^{-}$]}^{2} = s\times (2s)^{2} =  4s^{3}\\s^{3} = \dfrac{K_{sp}}{4}\\\\s =\mathbf{ \sqrt [3]{\dfrac{K_{sp}}{4}}}\\\\\text{The mathematical expressionthat can be used to determine the value of  }\mathbf{s =\sqrt [3]{\dfrac{K_{sp}}{4}}}

B)

The Concentration of Pb²⁺  in water is calculated as :

\mathbf{s =\sqrt [3]{\dfrac{K_{sp}}{4}}}

\mathbf{s =\sqrt [3]{\dfrac{7*10^{-9}}{4}}}

\mathbf{s} =\sqrt[3]{1.75*10^{-9}}

\mathbf{s} =\mathbf{1.21*10^{-3}  \ mol/L }

The Concentration of Pb²⁺  in 1.0 mol·L⁻¹ NaI

\mathbf{PbCl{_2}}  \leftrightharpoons    \ \ \ \ \ \ \  \mathbf{Pb^{2+}}   \ \ \ \  \ +   \ \  \ \ \ \ \ \mathbf{2 I^-}

                             \ \ \ \ \ \ \  \ \   \ \  \ \ \ \ \ \ \  \mathbf0}   \ \ \ \  \ \ \ \ \ \   \ \ \ \ \ \mathbf{1.0}

                            \ \ \ \ \ \ \ \ \ \ \ \ \ \    \ \ \ \ \  \mathbf{+x}   \ \ \ \  \    \ \  \ \ \ \ \ \mathbf{+2x}

                            \ \ \ \ \ \ \ \ \ \ \ \ \ \    \ \ \ \ \  \mathbf{+x}   \ \ \ \  \    \ \  \ \ \ \ \ \mathbf{1.0+2x}

The equilibrium constant:

K_{sp} =[Pb^{2+}}][I^-]^2 \\ \\ K_{sp} = s*(1.0*2s)^2 =7*1.0^{-9} \\ \\ s = 7*10^{-9} \ \  m/L

It is now clear that maximum possible concentration of Pb²⁺ in the solution is less than that in the solution in part (A). This happens due to the  common ion effect. The added iodide ion forces the position of equilibrium to shift to the left, reducing the concentration of Pb²⁺.

3 0
2 years ago
During a titration the following data were collected. A 10. mL portion of an unknown monoprotic acid solution was titrated with
Liula [17]

Answer:

8.0 moles

Explanation:

Since the acid is monoprotic, 1 mole of the acid will be required to stochiometrically react with 1 mole of NaOH.

Using the formula: \frac{concentration of acid X volume of acid}{concentration of base X volume of base} = \frac{mole of acid}{mole of base}

Concentration of acid = ?

Volume of acid = 10 mL

Concentration of base = 1.0 M

Volume of base = 40 mL

mole of acid = 1

mole of base = 1

Substitute into the equation:

\frac{concentration of acid X 10}{1.0 X 40} = \frac{1}{1}

Concentration of acid = 40/10 = 4.0 M

To determine the number of moles of acid present in 2.0 liters of the unknown solution:

Number of moles = Molarity x volume

molarity = 4.0 M

Volume = 2.0 Liters

Hence,

Number of moles = 4.0 x 2.0 = 8 moles

8 0
2 years ago
The mass of a container is determined to be 1.2 g. A sample of a compound is transferred to this container, and the mass of the
Nikitich [7]

Answer:

Sorry I don't know what you

3 0
1 year ago
Sodium acetate spontaneously crystallizes out of a supersaturated solution upon standing or upon the addition of a seed crystal.
AlekseyPX

Answer:

Option (c) is correct.

Explanation:

According to 2nd law of thermodynamics, every spontaneous process is associated with increase in entropy (\Delta S>0).

As sodium acetate crystallizes out spontaneously therefore it is associated with \Delta S>0.

During crystallization, bond formation takes place which results evolution of heat. In other words, crystallization phenomenon is exothermic (\Delta H).

So, the given crystallization process renders the following thermodynamic quantities- \Delta S>0 J/K and \Delta H J

Option (c) is correct.

6 0
2 years ago
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