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Svetllana [295]
1 year ago
10

The mass of a container is determined to be 1.2 g. A sample of a compound is transferred to this container, and the mass of the

compound plus the container is determined to be 3.06 g. The mass of the compound should be reported as:__.
Chemistry
1 answer:
Nikitich [7]1 year ago
3 0

Answer:

Sorry I don't know what you

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kirza4 [7]
The answer is C. It bans the exploitation of mineral resources 
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2 years ago
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You've just solved a problem and the answer is the mass of an electron, me=9.11×10−31kilograms. How would you enter this number
irina1246 [14]

Answer: 9.11\times 10^{-31}kg

Explanation:

Significant figures : The figures in a number which express the value or the magnitude of a quantity to a specific degree of accuracy is known as significant digits.

Rules for significant figures:

Digits from 1 to 9 are always significant and have infinite number of significant figures.

All non-zero numbers are always significant.

All zero’s between integers are always significant.

All zero’s after the decimal point are always significant.

All zero’s preceding the first integers are never significant.

Thus 9.11\times 10^{-31}kg has three significant figures

7 0
2 years ago
A 0.216 g sample of an aluminium compound X reacts with an excess of water to produce a single hydrocarbon gas. This gas burns c
makkiz [27]
0.216g of aluminium compound X  react with an excess of water water to produce gas. this gas burn completely  in O2  to form H2O and 108cm^3of CO2 only . the volume of CO2 was measured at room temperature and pressure

0.108 / n  =  24 / 1 
n = 0.0045 mole ( CO2 >>0.0045 mole 
0.216 - 0.0045 = 0.2115
so Al =   0.2115 / 27  =>  0.0078 mole 
C = 0.0045 * 1000 => 4.5    and Al  = 0.0078 * 1000 = 7.8 

7 0
2 years ago
BRAINLIESTTT ASAP!!!
Stels [109]

While I am not the brainliest I can certainly answer.  

This was a chemical change because the chemical components were changed, a big giveaway to this was the fizzing, however the temperature rising was also another giveaway.

8 0
2 years ago
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A mixture containing KClO3,K2CO3,KHCO3, and KCl was heated, producing CO2,O2, and H2O gases according to the following equations
Nikitich [7]

<u>Answer:</u>

<u>For 1:</u> The mass of KClO_3 in the original mixture is 10.46 g

<u>For 2:</u> The mass of KHCO_3 in the original mixture is 21.11 g

<u>Explanation:</u>

We are given:

Mass of water = 1.90 g

Mass of carbon dioxide = 13.64 g

Mass of oxygen = 4.10 g

  • <u>For 1:</u>

The given chemical reaction for decomposition of KClO_3 follows:

2KClO_3\rightarrow 2KCl+3O_2

By Stoichiometry of the reaction:

(3\times 32)=96g of oxygen is produced when (2\times 122.5)=245g of potassium chlorate is decomposed.

So, 4.10 g of oxygen will be produced when = \frac{245}{96}\times 4.10=10.46g of potassium chlorate is decomposed.

Amount of KClO_3 in the mixture = 10.46 g

  • <u>For 2:</u>

The given chemical reaction for decomposition of KHCO_3 follows:

2KHCO_3\rightarrow K_2O+H_2O+2CO_2

By Stoichiometry of the reaction:

18 g of water is produced when (2\times 100)=200g of potassium bicarbonate is decomposed.

So, 1.90 g of water will be produced when = \frac{200}{18}\times 1.90=21.11g of potassium bicarbonate is decomposed.

Amount of KHCO_3 in the mixture = 21.11 g

4 0
2 years ago
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