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Harrizon [31]
2 years ago
11

Process in which permanent deformation of metals occurs due to applied stress and results in breaking of bonds and then reformin

g of bonds with new neighbors. After removing of the stress, the metal does not return to its initial form.
Physics
1 answer:
luda_lava [24]2 years ago
6 0

Answer:

This process involves the motion of dislocations and is termed slip (or glide in some textbooks)

Explanation:

Plastic deformation of metals (and other crystalline materials) usually occurs by slip, which is the sliding of planes of atoms over one another by dislocation movements.

On a microscopic scale, stress causes planes of crystalline objects to leave their original position and slide over other planes into new positions, these microscopic movements manifest as a slip on a macroscopic scale. And the planes do not return back to their original position after the removal of the dislocation-causing stress.

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A strip 1.2 mm wide is moving at a speed of 25 cm/s through a uniform magnetic field of 5.6 t. what is the maximum hall voltage
Alex787 [66]
The equation for Hall voltage Vh is:

Vh=v*B*w, where v is the velocity of the strip, B is the magnitude of the magnetic field, and w is the width of the strip. 

v=25 cm/s = 0.25 m/s
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w= 1.2 mm = 0.0012 m

We input the numbers into the equation and get:

Vh= 0.25*5.6*0.0012 = 0.00168 V

The maximum Hall voltage is Vh= 0.00168 V.
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How can controlling the way light bends and reflects be used to help people?
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Assume that the particle has initial speed viviv_i. Find its final kinetic energy KfKfK_f in terms of viviv_i, MMM, FFF, and DDD
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Answer:

KE= 1/2mv²

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Light-rail passenger trains that provide transportation within and between cities speed up and slow down with a nearly constant
rosijanka [135]

Answer:

v_f = 13m/s + 0.75 \frac{m}{s^2} * 16 s= 13 m/s +12m/s = 25 m/s

Explanation:

For this case we know that the initial velocity is given by:

v_i = 7 \frac{m}{s}

The final velocity on this case is given by:

v_f = 13 \frac{m}{s}

And we know that it takes 8 seconds to go from 7m/s to 13m/s. We can use the following kinematic formula in order to find the acceleration during the first interval:

v_f = v_i +at

If we solve for the acceleration we got:

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So for the other traject we assume that the acceleration is constant and the train travels for 16 s. The initial velocity on this case would be 13m/s from the first interval and we can find the final velocity with the following formula:

v_f = v_ i +a t

And if we replace we got:

v_f = 13m/s + 0.75 \frac{m}{s^2} * 16 s= 13 m/s +12m/s = 25 m/s

5 0
2 years ago
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