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Reika [66]
2 years ago
6

The ends of a massless rope are attached to two stationary objects (e.g., two trees or two cars) so that the rope makes a straig

ht line. For this situation, which of the following statements are true?
a. The tension in the rope is everywhere the same.
b. The magnitudes of the forces exerted on the two objects by the rope are the same.
c. The forces exerted on the two objects by the rope must be in opposite directions.
d. The forces exerted on the two objects by the rope must be in the direction of the rope.
Physics
1 answer:
julia-pushkina [17]2 years ago
5 0

Answer: They are all true

a. The tension in the rope is everywhere the same.

b. The magnitudes of the forces exerted on the two objects by the rope are the same.

c. The forces exerted on the two objects by the rope must be in opposite directions.

d. The forces exerted on the two objects by the rope must be in the direction of the rope.

Hope this helps, now you know the answer and how to do it. HAVE A BLESSED AND WONDERFUL DAY! As well as a great rest of Black History Month! :-)  

- Cutiepatutie ☺❀❤

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A model train engine was moving at a constant speed on a straight horizontal track. As the engine moved​ along, a marble was fir
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Answer:

The marble was moving in a projectile and the speed of the engine was 2.716 m/s

Explanation:

The vertical component of the marble's flight path relative to the train

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So with y(1) = v - 4.9 = 0 we have  

v = 4.9 m/s.

The marble will reach maximum height after 0.5 seconds, at which the

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Now,  the marble has a vertical velocity component of 4.9 m/s and a horizontal velocity component

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This horizontal velocity component of the marble is the same as the

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3 0
2 years ago
The electric potential in a region that is within 2.00 mm of the origin of a rectangular coordinate system is given by V=Axl+Bym
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Answer:

Given the potential, V = Ax^l+By^m+Cz^n+D

The components of the electric field are:

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E_y = \frac{-dV}{dy} = - Bmy^m^-^1

E_z = \frac{-dV}{dz} = - nCzn^n^-^1

Let's calculate the potential difference for all given points.

V(0, 0, 0) = 10V => Ax^l+By^m+Cz^n+D = 10

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Solving for A, we have:

A = 4 - 10

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For all given points, let's calculate the magnitude of electric field as follow:

E_x (1, 0, 0) = 16 => - Alx^l^-^1 = 16

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Solving for l, we have:

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m = \frac{-16}{A}

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Solving for n, we have:

n = \frac{-16}{C}

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