Answer:a) 4+8+24=36
B) 1/4+1/8+1/24=10
C) yu will connect them in parallel connection.
D) you will connect two in parallel then the remaining one in series to the ons connected in parallel.
Explanation:
Answer:
string's damping is 1.03676
Explanation:
given data
sound level = 9.0 dB
time = 1 sec
to find out
string's damping
solution
we will apply here formula for string damping (b) that is
A(t) = A ×
...................1
we know here I ∝ A² so
√I(t) = √I ×
√I(t) / √I =
.....................2
we know sound level decreases 9 dB i.e ΔdB = 9
so we can write
ΔdB = 10 log ( I(t) / I)
9 = 10 log ( I(t) / I)
I(t) / I = 
I(t) / I = 0.1258
and
√I(t) / I) = √0.1258 = 0.3546 .......................3
from equation 2 and 3 we get
0.3546 = 
take ln both side
-bt = ln 0.3546
here we know t is 1 sec
so
- b = - 1.03676
b = 1.03676
so here string's damping is 1.03676
Answer:
option b
Explanation:
There is an object pulled inward in an electric field.
We have to find out of the four options given which is true.
a) The object has a neutral charge is false since when electric field pulls the object inward, there is a charge inside.
b) The object has a charge opposite that of the field, this option is correct since there will be an equal and opposite charge created by the object
c) The object has a negative charge will be correct only if the original charge was positive hence wrong
d) The object has a charge the same as that of the field is incorrect since this would be opposite the charge
So only option b is right
Answer:
a) Velocity = 4.2m/s
b) Acceleration = 2.94m/s^2
c) Force exerted on the floor= 1401.4×10^3N
Explanation:
a) Velocity,V=sqrt(2×9.8×0.900)
V= 4.2m/s
b) Vf2= V^2+2ay2
a= 4.2^2 - 0/2×3
a= 17.64/6= 2.94m/s^2
c) Newton's 2nd law indicates:
Fnet= F - mg=ma
F= m(g+a)
F=110(9.8+2.94)
F=110×12.94
F= 1401.4N
Answer: C.
Explanation:
i choose B and got it wrong it told me the answer after on edge.