A sample of radioactive waste has a half-life of 10 years and an activity level of 2 curies. After how many years will the activ
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Answer:
The magnitude of the force on the dipole due to the charge Q =
The magnitude of the torque on the dipole =
Explanation:
Given that a point charge Q is held at a distance r from the center of a dipole that consists of two charges ±q, separated by a distance s and the charge Q is located in the plane that bisects the dipole.
The magnitude of the electric field that the dipole exerts at the position where the charge Q is held is given by
<em>where</em>,
k is the Coulomb's constant, having value =
is the electrical permittivity of free space.
Also, r>>s, therefore,
The magnitude of the electric force F on a charge q placed at a point and the magnitude of the electric field E at that point are related as
Therefore, the electric force on the charge Q due to the dipole is given by
According to Newton's third law of motion, the magnitude of the force exerted by the dipole on the charge Q is same as the magnitude of the force exerted by the charge on the dipole.
Thus, the magnitude of the force on the dipole due to the charge Q =
The magnitude of the torque on the dipole is given by
Since the charge Q is placed in the plane that bisects the dipole, therefore, .
Answer:
The value of total energy needed per minute for the humidifier = 77.78 KJ
Explanation:
Total energy per minute the humidifier required = Energy required to heat water to boiling point) + Energy required to convert liquid water into vapor at the boiling point) ----- (1)
Specific heat of water = 4190
The heat of vaporization is = 2256
Mass = 0.030 kg
Energy needed to heat water to boiling point =
Energy needed to heat water to boiling point = 0.030 × 4.19 × (100 - 20)
Energy () = 10.08 KJ
Energy needed to convert liquid water into vapor at the boiling point
= 0.030 × 2256 = 67.68 KJ
Thus the total energy needed E = +
E = 10.08 + 67.68
E = 77.78 KJ
This is the value of total energy needed per minute for the humidifier.