answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
s344n2d4d5 [400]
2 years ago
8

5. Glycogen and starch both give a (+) test with I2-KI and a (-) test with Benedict's. If you hydrolyzed these two polysaccharid

es and tested the solutions with the same two reagents what results would you get? Explain these results.
Chemistry
1 answer:
SVETLANKA909090 [29]2 years ago
3 0

Answer:

There will be no reaction between the product of hydrolysis and I2-KI (-ve). When the product of hydrolysis is tested with Benedict reagent, a brick-red precipitate is observed.

Explanation:

Benedict's reagent as a chemical reagent is a mixture of sodium carbonate, sodium citrate and copper(II) sulfate pentahydrate. It is often used in place of Fehling's solution to detect the presence of reducing sugars. A positive test with Benedict's reagent is shown by a color change from clear blue to a brick-red precipitate.

Glycogen and starch are both complex structures containing repeating units of glucose(a reducing sugar). The polysaccharides have non redusing ends and so cannot react with benedict reagent.

When they are hydrolysed, glucose which is a reducing sugar can then test positive with Benedict reagent.

You might be interested in
Which products would result from the double replacement reaction between mgcl2(aq) and na2co3(aq)?
Andrew [12]
Double displacement reactions are when the cations and anions of 2 compounds are exchanged. Cation of one reactant will form a new product with the anion of the other reactant and vice versa.
MgCl₂ --> Mg²⁺  + 2Cl⁻
Na₂CO₃ --> 2Na⁺ + CO₃²⁻
the cations and anions are exchanged therefore double displacement reaction is as follows;
MgCl₂(aq) + Na₂CO₃(aq) --> MgCO₃(s) + 2NaCl(aq)
8 0
1 year ago
From gross and specific selection rules below, identify which belongs to the rotational, rotational Raman, vibrational and elect
guajiro [1.7K]

Answer:

Rotational spectroscopy, the dipole moment must change during the transition.

Rotational Raman spectroscopy, molecule must have anisotropic polarizability

Vibrational and electronic spectroscopy, molecule must have permanent dipole moment.

Explanation:

  • For the vibration rotation spectrum to be observed, it is necessary to change the dipole moment during the vibration.
  • Raman scattering using an anisotropic crystal gives information about the orientation of the crystal. The polarization of Raman scattering light relative to the crystal, and the polarization of laser light, can be used to determine the orientation of the crystal, provided the crystal structure is known.
8 0
1 year ago
What is the specific heat of a metal if the temperature of a 12.5 g sample increases from 19.5 C to 33.6 C when it absorbs 37.7
MariettaO [177]

Answer:

0.213 J/g°C

Explanation:

To calculate specific heat of the metal, the formula is used:

Q = m × c × ∆T

Where Q = amount of heat

m = mass

c = specific heat

∆T = change in temperature

According to this question, Q = 37.7 J, m= 12.5 g, initial temperature= 19.5 °C, final temperature = 33.6°C, c=?

Q = m × c × ∆T

37.7 = 12.5 × c × (33.6-19.5)

37.7 = 12.5c × 14.1

37.7 = 176.25c

c = 37.7/176.25

c = 0.2139

Hence, the specific heat of the metal is 0.213 J/g°C

8 0
2 years ago
How would you know if this combination is likely to be found in some dirt?
Mkey [24]

Answer:

  very unlikely to be found in dirt

Explanation:

That combination has a ratio of ¹⁴N to ¹⁵N of 10:4 = 2.5: 1. The most ¹⁵N enriched natural material has a ratio of ¹⁴N to ¹⁵N on the order of 250 : 1 or higher. The combination shown is very unlikely to be found in dirt.

6 0
1 year ago
Chromium (III) forms a complex with diphenylcarbazide whose molar absorptivity is 4.17x104 at 540 nm.
son4ous [18]

Answer:

3.00 cm

Explanation:

The absorbance can be expressed using <em>Beer-Lambert's law</em>:

A = ε*b*c

Where ε is a constant for each compound, b is the optical path, and c is the molar concentration of the compound.

Now we <u>match the absorbance values for both solutions</u>, because we want the absorbance value to be the same for both solutions:

A = ε * 1.00 cm * 7.68x10⁻⁶M = ε * b * 2.56x10⁻⁶ M

And <u>solve for b:</u>

 ε * 1.00 cm * 7.68x10⁻⁶M = ε * b * 2.56x10⁻⁶ M

1.00 cm * 7.68x10⁻⁶M = b * 2.56x10⁻⁶ M

b = 3.00 cm

5 0
2 years ago
Other questions:
  • How is the periodic law demonstrated in halogens
    10·2 answers
  • Which is a component of John Dalton’s atomic theory? The ratio of atoms in a compound is fixed. The atoms of different elements
    11·2 answers
  • If a particular ore contains 55.4 % calcium phosphate, what minimum mass of the ore must be processed to obtain 1.00 kg of phosp
    11·1 answer
  • explain how energy changes from one form to another in a exothermic reaction. in an endothermic reaction.
    11·1 answer
  • A flask of fixed volume contains 1.0 mole of gaseous carbon dioxide and 88 g of solid carbon dioxide. The original pressure and
    14·1 answer
  • The density of an unknown crystal is 2.65gmL. If a 4.46 g sample of the crystal is added to a graduated cylinder containing 25.0
    6·1 answer
  • The term nuclear charge refers to the precise charge of the nucleus, which, in units of fundamental charge, is equal to the numb
    5·1 answer
  • A metal, M , of atomic mass 56 amu reacts with chlorine to form a salt that can be represented as MClx. A boiling point elevatio
    8·1 answer
  • Both hydrogen sulfide (H2S) and ammonia (NH3) have strong, unpleasant odors. Which gas has the higher effusion rate? If you open
    10·1 answer
  • During a lab experiment performed at STP conditions, you prepare HCl by reacting 100. ml of Cl2 gas with an excess of H2 gas.
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!