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Evgesh-ka [11]
2 years ago
14

Tas watches as his uncle changes a flat tire on a car. His uncle raises the car using a machine called a jack. Each time his unc

le pushes down on the jack handle, the car rises up. Tas sketches the jack and labels it using the symbols F, to represent force, and d, to represent distance. He uses large and small letters to compare the sizes of the forces and distances.
Which set of labels is correct for the side of the jack that Tas’s uncle pushes on?

A-a large F and a small d
B-a small F and a small d
C-a large F and a large d
D-a small F and a large d
Physics
2 answers:
Allisa [31]2 years ago
6 0

Answer:

D) -a small F and a large d

Explanation:

As per Pascal's law we know that the pressure applied to any point of the fluid is equally transmitted to all points of the fluid.

So here we can say that when we apply some pressure at the input point then that pressure will be equally transmitted to all points

So here we have

P = \frac{F_{in}}{A_{in}} = \frac{F_{out}}{A_{out}}

so here in order to have large output force we can say

F_{out} = \frac{F_{in}}{A_{in}}\times A_{out}

so we need to apply smaller force so that we will get bigger value of the distance that the jack will move upwards.

so correct answer will be

<em>D)-a small F and a large d</em>

baherus [9]2 years ago
3 0
Hydraulic jacks work<span> based off of Pascal's Principle, which states that pressure is equal throughout an enclosed container. When force is applied to the small cylinder, the pressure in the cylinder gets greater. By Pascal's Principle, this means pressure in the larger cylinder gets greater as well. so the correct answer is a small F and a large d</span>
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Explanation:

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You may have noticed runaway truck lanes while driving in the mountains. These gravel-filled lanes are designed to stop trucks t
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Answer:

The  coefficient of kinetic friction  \mu_k =  0.724

Explanation:

From the question we are told that

   The  length of the lane is  l =  36.0 \  m

    The speed of the truck is  v  =  22.6\  m/s

     

Generally from the work-energy theorem we have that  

    \Delta KE  =   N  *  \mu_k *  l

Here N  is the normal force acting on the truck which is mathematically represented as

     \Delta KE is the change in kinetic energy which is mathematically represented as

        \Delta KE =  \frac{1}{2} *  m *  v^2

=>     \Delta KE =  0.5  *  m *  22.6^2

=>      \Delta KE =  255.38m

        255.38m =    m *  9.8  *  \mu_k *   36.0

=>     255.38  =    352.8  *  \mu_k

=>   \mu_k =  0.724

 

6 0
2 years ago
A truck pulled a car of 2,350 kg a distance of 25 meters. If the car accelerates from 3 m/s to 6 m/s, whats the average force ex
faust18 [17]

Answer:

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Explanation:

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To prevent collisions and violations at intersections that have traffic signals, use the _____ to ensure the intersection is cle
Ann [662]
The answer should be:
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3 0
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A pet-store supply truck moves at 25.0 m/s north along a highway. inside, a dog moves at 1.75 m/s at an angle of 35.0° east of
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<u>Answer:</u>

 Velocity of the dog relative to the road = 26.04 m/s 3.15⁰ north of east.

<u>Explanation:</u>

  Let the east point towards positive X-axis and north point towards positive Y-axis.

  Speed of truck = 25 m/s north = 25 j m/s

  Speed of dog = 1.75 m/s at an angle of 35.0° east of north = (1.75 cos 35 i + 1.75 sin 35 j)m/s

                          = (1.43 i + 1.00 j) m/s

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 So Velocity of the dog relative to the road = 26.04 m/s 86.85⁰ east of north = 26.04 m/s 3.15⁰ north of east.

4 0
2 years ago
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