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Leya [2.2K]
2 years ago
11

ou purchase a rectangular piece of metal that has dimen- sions 5.0 * 15.0 * 30.0 mm and mass 0.0158 kg. The seller tells you tha

t the metal is gold. To check this, you compute the average density of the piece. What value do you get? Were you cheated?
Physics
1 answer:
Natalija [7]2 years ago
4 0

Answer: 7022.2kg/m³, yes, I was cheated

Explanation:

Density of an object is defined as the ratio of the mass of the object to its volume. Mathematically;

Density = Mass/Volume

Note that the unit of both mass and volume must be standard unit.

Given mass = 0.0158kg

Dimension of the metal = 5mm×15mm×30mm

Note that 1mm = 0.001m

The volume of the metal will be

0.005×0.015×0.03

= 0.00000225m³

Density = 0.0158/0.00000225

Average density of the metal = 7022.2kg/m³

Since the standard density of Gold is 19,320kg/m³ and is higher than the density prescribed for me, it shows the I was cheated.

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A typical automobile under hard braking loses speed at a rate of about 7.2 m/s2; the typical reaction time to engage the brakes
Korvikt [17]

Answer:

4.3 m/s

Explanation:

a = rate at which the automobile loses speed = - 7.2 m/s²

v₀ = initial maximum speed of automobile

t' = reaction time for applying the brakes = 0.55 s

d = distance available for stopping the vehicle = 3.6 m

d' = distance traveled while applying the brakes = v₀ t' = (0.55) v₀

v = final speed after the vehicle comes to stop = 0 m/s

Using the equation

v² = v₀² + 2 a (d - d' )

0² =  v₀² + 2 (- 7.2) (3.6 -  (0.55) v₀)

v₀ = 4.3 m/s

7 0
2 years ago
A beam of unpolarized light shines on a stack of five ideal polarizers, set up so that the angles between the polarization axes
ddd [48]

Answer:

21.75

Explanation:

n = number of polarizers through which light pass through = 5

\theta = Angle between each pair of adjacent polarizers

I_{o} = Intensity of unpolarized light

I_{n} = Intensity of transmitted beam after passing all polarizers

It is given that

\frac{I_{n}}{I_{o}}= 0.277

we know that the intensity of light after passing through "n" polarizers is given as

I_{n} = (0.5) I_{o} Cos^{2n-2}\theta

\frac{I_{n}}{I_{o}} = (0.5) Cos^{2n-2}\theta

inserting the values

0.277 = (0.5)Cos^{2(5)-2}\theta

0.554 = Cos^{8}\theta

Cos\theta = 0.9288

\theta = Cos^{-1}(0.9288)

\theta = 21.75

7 0
2 years ago
Several charges in the neighborhood of point P produce an electric potential of 6.0 kV (relative to zero at infinity) and an ele
Julli [10]

Answer:

0.018 J

Explanation:

The work done to bring the charge from infinity to point P is equal to the change in electric potential energy of the charge - so it is given by

W = q \Delta V

where

q=3.0 \mu C = 3.0 \cdot 10^{-6} C is the magnitude of the charge

\Delta V = 6.0 kV = 6000 V is the potential difference between point P and infinity

Substituting into the equation, we find

W=(3.0\cdot 10^{-6}C)(6000 V)=0.018 J

4 0
2 years ago
If one replaces the conducting cube with one that has positive charge carriers, in what direction does the induced electric fiel
Grace [21]

Answer:

There will be no change in the direction of the electric field .

Explanation:

The direction will remain the same because the sign of the charges has no effect on it.

When one replaces the conducting cube with one that has positive charge carriers there will be no change in the direction of the field as there is no defined relationship between the direction of the electric field and sign of the charge.

3 0
2 years ago
A blue puck has a velocity of 0i – 3j m/s and a mass of 4 kg. A gold puck has a velocity of 12i – 5j m/s and a mass of 6 kg. Wha
Mnenie [13.5K]
By definition, the kinetic energy is given by:
 K = (1/2) * m * v ^ 2
 where
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 v = speed
 We must then find the speed of both objects:
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 gold puck
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 K = (1/2) * (4) * (3 ^ 2) + (1/2) * (6) * (13 ^ 2)
 K = <span> 525</span> J
 answer
 The kinetic energy of the system is<span> <span>525 </span></span>J
6 0
2 years ago
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