Question

Two bars are conducting heat from a region of higher temperature to a region of lower temperature. The bars have identical lengths and cross-sectional areas, but are made from different materials. In the drawing they are placed "in parallel" between the two temperature regions in arrangement A, whereas they are placed end to end in arrangement B. In which arrangement is the heat that is conducted the greatest?

Answer 1

Answer:

Arrangement A will have a greater heat transfer

Explanation:

the rate of heat conduction between two materials of different temperatures is given as

$\frac{\Delta Q}{\Delta t}=\frac{-KA \Delta T}{ L}$

This formula shows the following:

• An increased equivalent cross sectional area between the two transferring bodies will in crease the rate of heat transfer.
• A reduction in length of medium will increase the rate if heat transfer

Arrangement A has a shorter transfer medium and a larger equivalent cross sectional area, because the two rods are arranged in a parallel configuration.

whereas, Arrangement a has a longer transfer medium and a smaller cross sectional area, since the two rods are arranged end to end