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goblinko [34]
2 years ago
5

A boy ties a stone to the end of a string which he then whirles above his head round a circular path of radius 15cm. if the ston

e makes 20 oscillations in 10 seconds calculate the angular and linear speeds of the stone.​
Physics
1 answer:
STALIN [3.7K]2 years ago
3 0

Answer:

W = 12.568rads

V = 1.8852m/s

Explanation:

Data:

r = 15cm = 0.15m

t = 10s

Revolutions = 20

Frequency (F) = number revolutions/ time take complete it

F = 20 / 10 = 2Hz

Angular velocity (w) = 2 * 3.142 * F

Note: 3.142 = value of pi

W = 2*3.142*2 = 12.568 rads

Linear velocity (v) = w*r

V = 12.568*0.15 = 1.8852m/s

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2.0 kg of solid gold (Au) at an initial temperature of 1000K is allowed to exchange heat with 1.5 kg of liquid gold at an initia
Elanso [62]

Answer:

Explanation:

The specific heat of gold is 129 J/kgC

It's melting point is 1336 K

It's Heat of fusion is 63000 J/kg

Assuming that the mixture will be solid, the thermal energy to solidify the gold has to be less than that needed to raise the solid gold to the melting point. So,

The first is E1 = 63000 J/kg x 1.5 = 94500 J

the second is E2 = 129 J/kgC x 2 kg x (1336–1000)K = 86688 J

Therefore, all solid is not correct. You will have a mixture of solid and liquid.

For more detail, the difference between E1 and E2 is 7812 J, and that will melt

7812/63000 = 0.124 kg of the solid gold

8 0
2 years ago
A bar 4.0m long weights 400 N. Its center of gravity is 1.5m from on end. A weight of 300N is attached at the light end. What ar
Debora [2.8K]

Answer:

The resulting, needed force for equilibrium is a reaction from a support, located at 2.57 meters from the heavy end. It is vertical, possitive (upwards) and 700 N.

Explanation:

This is a horizontal bar.

For transitional equilibrium, we just need a force opposed to its weight, thus vertical and possitive (ascendent). Its magnitude is the sum of the two weights, 400+300 = 700 N, since weight, as gravity is vertical and negative.

Now, the tricky part is the point of application, which involves rotational equilibrium. But this is quite simple if we write down an equation for dynamic momentum with respect to the heavy end (not the light end where the additional weight is placed). The condition is that the sum of momenta with respect to this (any) point of the solid bar is zero:

0=\Sigma_{i}M=400\cdot1.5+300\cdot4-d\cdot700

Where momenta from weights are possitive and the opposed force creates an oppossed momentum, then a negative term. Solving our unknown d:

d=\frac{400\cdot1.5+300\cdot4}{700} =2.57 m

So, the resulting force is a reaction from a support, located at 2.57 meters from the heavy end (the one opposed to the added weight end).

8 0
2 years ago
Use Kepler’s third law and the orbital motion of Earth to determine the mass of the Sun. The average distance between Earth and
Anna11 [10]

Kepler’s third law formula: T^2=4pi^2*r^3/(GM)

We’re trying to find M, so:

M=4pi^2*r^3/(G*T^2)

M=4pi^2*(1.496 × 10^11 m)^3/((6.674× 10^-11N*m^2/kg^2)*(365.26days)^2)

M=1.48× 10^40(m^3)/((N*m^2/kg^2)*days^2))

Let’s work with the units:

(m^3)/((N*m^2/kg^2)*days^2))=

=(m^3*kg^2)/(N*m^2*days^2)

=(m*kg^2)/(N*days^2)

=(m*kg^2)/((kg*m/s^2)*days^2)

=(kg)/(days^2/s^2)

=(kg*s^2)/(days^2)

So:

M=1.48× 10^40(kg*s^2)/(days^2)

Now we need to convert days to seconds in order to cancel them:

1 day=24 hours=24*60minutes=24*60*60s=86400s

M=1.48× 10^40(kg*s^2)/((86400s)^2)

M=1.48× 10^40(kg*s^2)/( 86400^2*s^2)

M=1.48× 10^40kg/86400^2

M=1.98x10^30kg

The closest answer is 1.99 × 10^30

(it may vary a little with rounding – the difference is less than 1%)

5 0
2 years ago
Read 2 more answers
You traveled 150.meters south at a speed of 1.50m/s, and then traveled 600. Meters north at a rate of 2.00 m/s.
Jlenok [28]

Answer:

1.) 400s

2.) 1.875 m/s

3.) 1.125 m/s

Explanation:

Given that you traveled 150.meters south at a speed of 1.50m/s,

Time = distance/ speed

Substitute speed and distance into the formula

Time = 150/1.5

Time = 100 s

and then traveled 600. Meters north at a rate of 2.00 m/s.

Time = 600 / 2

Time = 300 s

1.) Total time = 100 + 300

Total time = 400 s

2.) The average speed will be total distance travelled over total time.

Total distance travelled = 150 + 600

Total distance travelled = 750 m

Substitute all the parameters into the formula

Average speed = 750/400

Average speed = 1.875 m/s

3.) Average velocity will be displacement over total time

Displacement = 600 - 150

Displacement = 450 m

Average velocity = 450/400

Average velocity = 1.125 m/s

6 0
2 years ago
A heat engine absorbs 64 kcal of heateach cycle and exhausts 42 kcal. Calculate the efficiency of eachcycle. (Page Ref: Sec. 15.
Dahasolnce [82]

Answer:

The efficiency of each cycle of a heat engine is 30 %.                                                            

Explanation:

Given that,

Heat absorbed by a heat engine, Q = 64 kcal

Heat exhaust by a heat engine, Q' = 42 kcal

We need to find the efficiency of each cycle. The efficiency of heat engine is defined as the ratio of work output to the energy supplied. It is given by :

\eta=1-\dfrac{Q'}{Q}

\eta=1-\dfrac{42}{64}

\eta=0.3

or

\eta=30\%

So, the efficiency of each cycle of a heat engine is 30 %. Hence, this is the required solution.

4 0
2 years ago
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