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Temka [501]
1 year ago
5

2.0 kg of solid gold (Au) at an initial temperature of 1000K is allowed to exchange heat with 1.5 kg of liquid gold at an initia

l temperature at 1336K. The solid and liquid can only exchange heat with each other. What kind of analysis do you need to perform in order to determine whether, once thermal equilibrium is reached, the mixture will be entirely solid or in a mixed solid/liquid phase?
Physics
1 answer:
Elanso [62]1 year ago
8 0

Answer:

Explanation:

The specific heat of gold is 129 J/kgC

It's melting point is 1336 K

It's Heat of fusion is 63000 J/kg

Assuming that the mixture will be solid, the thermal energy to solidify the gold has to be less than that needed to raise the solid gold to the melting point. So,

The first is E1 = 63000 J/kg x 1.5 = 94500 J

the second is E2 = 129 J/kgC x 2 kg x (1336–1000)K = 86688 J

Therefore, all solid is not correct. You will have a mixture of solid and liquid.

For more detail, the difference between E1 and E2 is 7812 J, and that will melt

7812/63000 = 0.124 kg of the solid gold

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"I know how many electrons the atom has, and I know how many protons it has, but I don't know whether or not it is neutral," a f
finlep [7]

The atom is neutral (no electric charge)

Explanation:

An atom consists of:

- A nucleus, containing protons (positively charged) and neutrons (no electric charge)

- Electrons (negatively charged), orbiting around the nucleus

The charge of one proton is equal in magnitude (but opposite in sign) to that of an electron, and it is

e=1.6\cdot 10^{-19} C

Moreover, for a normal atom, the number of protons in the nucleus is equal to the number of electrons around it.

This means that for a normal atom, the net charge of it is zero, since the total charge of the protons balance that of the electrons.

So, the answer to the question is that the atom is neutral.

Learn more about atoms here:

brainly.com/question/2757829

#LearnwithBrainly

4 0
1 year ago
How and why does the distance between 2 electrodes affect the rate of electrolysis? ...?
Rasek [7]
 <span>Nothing, in terms of the chemistry. 

The distance between the electrodes affects the electrical resistance very slightly. Increasing the distance increases the resistance and reduces the current slightly, which reduces slightly the amount of product. 

For most practical applications, for electrolysis done in a beaker, varying the distance between the electrodes will make little difference. 

Increasing the concentration of the electrolyte will increase the current flow because there are more charged particles to carry charge, and increase the product yield.</span>
4 0
1 year ago
A 4.0 Ω resistor, an 8.0 Ω resistor, and a 12.0 Ω resistor are connected in parallel across a 24.0 V battery. What is the equiva
dsp73

PART A)

Equivalent resistance in parallel is given as

\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}

now we have

\frac{1}{R} = \frac{1}{4} + \frac{1}{8} + \frac{1}{12}

R = 2.18 ohm

PART B)

since potential difference across all resistance will remain same as all are in parallel

so here we can use ohm's law

V = iR

for 4 ohm resistance we have

24 = 4(i)

i = 6 A

PART C)

since potential difference across all resistance will remain same as all are in parallel

so here we can use ohm's law

V = iR

for 8 ohm resistance we have

24 = 8(i)

i = 3 A

3 0
2 years ago
Read 2 more answers
You are designing a generator with a maximum emf 8.0 V. If the generator coil has 200 turns and a cross-sectional area of 0.030
shutvik [7]

Answer:

7.1 Hz

Explanation:

In a generator, the maximum induced emf is given by

\epsilon= 2\pi NAB f

where

N is the number of turns in the coil

A is the area of the coil

B is the magnetic field strength

f is the frequency

In this problem, we have

N = 200

A=0.030 m^2

\epsilon=8.0 V

B = 0.030 T

So we can re-arrange the equation to find the frequency of the generator:

f=\frac{\epsilon}{2\pi NAB}=\frac{8.0 V}{2\pi (200)(0.030 m^2)(0.030 T)}=7.1 Hz

4 0
1 year ago
Read 2 more answers
In a simple circuit a 6-volt dry cell pushes charge through a single lamp which has a resistance of 3 Ω. According to Ohms law t
RSB [31]

Answer:

The answers and workings is in the Explanation section

Explanation:

<em>In a simple circuit a 6-volt dry cell pushes charge through a single lamp which has a resistance of 3 Ω. According to Ohms law the current through the circuit is _____________ Amps. </em>

According to Ohm’s law V =I*R  

Where V = Voltage, I = Current and R = Resistance

I = V/R =6/3 =2 Amps of current

Answer = 2 Amps

<em> If a second identical lamp is connected in series, the 6-volt battery must push a charge through a total resistance of ________ Ω</em>.  <em>The current in the circuit is then __________ Amps. </em>

Since the second lamp is connected in series with the first, the total resistance will R₂ = 3 + 3 = 6Ω

2 resistance in series  R₂ =  6Ω

The current in the circuit with the two lamps connected in series is I₂ =V/R₂ =6/6 = 1 Amps

The current is 1 Amps

Answer =  6Ω  and 1 Amps

<em>If a third identical lamp is connected in series, the total resistance is now _________Ω.  The current through all three lamps in series is now _________ Amps.  </em>

Since the third lamp is connected in series with the first and second, the total resistance will R₃ = 3 + 3 + 3 = 9Ω

total resistance of the 3 lamps R₃ =  9Ω

The current in the circuit with the three lamps connected in series is

I =V/R₃ =6/9 = 0.67 Amps

The current through the 3 lamps I₃ = 0.67 Amps

Answer =  9Ω  and 0.67 Amps

<em>The current through each individual lamp is __________ Amps.  </em>

Since all 3 lamps are connected in series, the same current will flow through each of the  3 lamps, and that current is I₃  

The current through each individual lamp is 0.67 Amp

Answer = 0.67 Amp

<em>What is the power when a voltage of 120 volts drives a current of 3 amps through a device?  </em>

The formula for power P = I*V =120*3 = 360 Watts

power P  = 360 Watts

Answer = 360 Watts

<em>What is the current when a 90-W light bulb is connected to 120 V? </em>

From P =I*V, make I the subject of the formula, I = P/V =90/120 = 0.75

Current= 0.75 Amps

Answer =  0.75 Amps

<em>How much current does a 75-W light bulb draw when connected to 120 V?</em>  

Current I =P/V = 75/120 = 0.625 Amps.

Answer = 0.625 Amps

<em>If part of an electric circuit dissipates energy at 6 W when it draws a current of 3 A, what voltage is impressed across it? </em>

Voltage V =P/I =6/3 =2 Volts

Answer = 2 Volts

<em> If a 60 W light bulb at 120 V is left on in your house to prevent burglary, and the power company charges 10 cents per kilowatt-hour, how much will it cost to leave the bulb on for 30 days? Show your work. </em>

24 hours make 1 day, so the number of hours the bulb was left on = 24 *30 = 720 hours

The power rating of the bulb is 60W = 60/1000 = 0.06 KiloWatt

Total power consumed in kilowatt-hour = 0.06 * 720 = 43.2 kilowatt-hour

Cost for 30 days = 0.1*43.2 = $4.32 ( note that 10 Cents = $0.1)

Answer =  $4.32

4 0
1 year ago
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