<h2>Answer:</h2>
<u>This term shows the </u><u>mass of the space shuttle</u>
<h2>Explanation:</h2>
We know that the mass of the Earth is 5.972 × 10^24 kg. Similarly the sum of mass of earth and the mass of shuttle must be a greater number as compared to the number given. It simply means that the mass of earth is itself 5.972 × 10^24 kg and the value given is 3 × 105 kg so it is obvious that if was the sum then it must be greater than the mass of earth. Therefore we can say that this not the mass of earth, neither the sum of mass of earth and shuttle, but this is only the mass of space shuttle which is the last multiple choice.
Jogger moves in three displacements
d1 = 10 blocks East
d2 = 5 blocks South
d3 = 2 blocks East
now we can say
total displacement towards East direction will be

Total displacement towards South

now to find the net displacement we can use vector addition



<em>so magnitude of net displacement will be equal to 13 blocks</em>
Answer:R=1607556m
θ=180degrees
Explanation:
d1=74.8m
d2=160.7km=160.7km*1000
d2=160700m
d3=80m
d4=198.1m
Using analytical method :
Rx=-(160700+75*cos(41.8))= -160755.9m
Ry= -(74.8+75sin(41.8))-198.1=73m
Magnitude, R:
R=√Rx+Ry
R=√160755.9^2+20^2=160755.916
R=160756m
Direction,θ:
θ=arctan(Rx/Ry)
θ=arctan(-73/160755.9)
θ=-7.9256*10^-6
Note that θ is in the second quadrant, so add 180
θ=180-7.9256*10^6=180degrees
Answer:
A. Increase in temperature is 0.0176 degree Celsius. b. the remaining energy will be lost.
Explanation:
The mass of copper block = 7kg
Initial speed = 4.0 m/s
Specific heat of copper = 0.385 j/g degree Celcius.
a. The increase in temperature is calculated below:

85% of energy is converted into internal energy.

b. The remaining 15 per cent of kinetic energy will be lost and it will be changed into other forms.
Answer:
Part a) When collision is perfectly inelastic

Part b) When collision is perfectly elastic

Explanation:
Part a)
As we know that collision is perfectly inelastic
so here we will have

so we have

now we know that in order to complete the circle we will have


now we have

Part b)
Now we know that collision is perfectly elastic
so we will have

now we have

