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Ivahew [28]
2 years ago
13

An investment of P dollars increased to A dollars in t years. If interest was compounded continuously, find the interest rate. (

Round your answer to the nearest whole number.)
A = 4482, P = 1000, t = 25
Mathematics
1 answer:
Gemiola [76]2 years ago
5 0

Answer: the interest rate is 6%

Step-by-step explanation:

The formula for continuously compounded interest is

A = P x e (r x t)

Where

A represents the future value of the investment after t years.

P represents the present value or initial amount invested

r represents the interest rate

t represents the time in years for which the investment was made.

e is the mathematical constant approximated as 2.7183.

From the information given,

A = $4482

P = 1000

t = 25 years

Therefore,

4482 = 1000 x 2.7183^(r x 25)

4482/1000 = 2.7183^25r

4.482 = 2.7183^25r

Taking ln of both sides, it becomes

Ln 4.482 = 25rLn2.7183

1.5 = 25r

r = 1.5/25 = 0.06

r = 0.06 × 100 = 6%

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Answer:

As per the given statement:

The region bounded by the given curves about the y-axis, y = 13e^{-x^2}, y=0, x = 0 and x = 1

Using cylindrical shell method:

The volume of solid(V) is obtained by rotating about y-axis and the region under the curve y = f(x) from a to b is;

V = \int_{a}^{b} 2\pi x f(x) dx   where 0\leq a

where x is the radius of the cylinder

f(x) is the height of the cylinder.

From the given figure:

radius = x

height(h) =f(x) =y=13e^{-x^2}

a = 0 and b = 1

So, the volume V generated by rotating the given region:

V =2 \pi \int_{0}^{1} x ( 13e^{-x^2}) dx\\\\V=2\pi\left [ -\frac{13}{2}e^{-x^2} \right ]_{0}^{1}\\\\V=2\pi\left (-\frac{13}{2e}-\left(-\frac{13}{2}\right) \right )\\\\V=-\frac{13\pi }{e}+13\pi

therefore, the volume of V generated by rotating the given region is V=-\frac{13\pi }{e}+13\pi










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. Cara is playing a game. For each dart she can toss onto a board, she
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A farmer kept 96 kilograms of animal feed in his barn.
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Answer:

<em>The amount of animal feed left was 86.4 kilograms.</em>

Step-by-step explanation:

Initial amount of animal feed in the barn was 96 kilograms.

The barn leaked and  \frac{1}{10} of the feed was wasted.

So, <u>the amount of feed wasted</u> =\frac{1}{10}(96)=9.6 kilograms.

<em>Now, for finding the amount of feed that was left, we need to subtract the amount of wasted feed from the initial amount of feed.</em>

So, the amount of animal feed left =(96-9.6)\ kilograms=86.4\ kilograms

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Taking,

x = miles above the sea-level

y = pressure in lb/in²

0         14.7

3.6         7.35

7.2         3.675

10.8         1.8375

It can be observed that both the variables are in inverse proportion as the distance from sea-level increase the pressure decreases.

As only the second graph satisfies the points and inverse proportional condition, so that is the correct graph.

By plotting the graph in excel taking these data set, the following plot was obtained.

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Approximate the area under the curve y = x² from x = 2 to x = 5 using a Right Endpoint approximation with 6 subdivisions.
Tanzania [10]

Answer:

\text{Area}\,=36.75

Step-by-step explanation:

Using right estimation point simply means to form a bunch of rectangles between the two limits, x =2 and x = 5. and add the areas of all those rectangles.

There must be 6 subdivisions between 2 and 5. so, to do that:

\Delta{x}=\dfrac{5-2}{6}=0.5

the length of each subdivision is 0.5 units. That also means that the 6 rectangles in between the limits will each have the base length of 0.5 units.

So the endpoints of each subdivision from 3 to 5 will be:

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By <em>right </em>endpoint approx<em>, </em>we mean that the height of the rectangles will be determined by the right endpoint of each subdivision, that is, it must be equal to the function value of the first limit.

\begin{tabular}{|c|c|c|}subdivision&$x$&height($y=x^2$)&3 to 3.5&3.5&12.25&3.5 to 4&4&16&4 to 4.5&4.5&20.25&4.5 to 5&5&25\end

Note that we have used the right-end-point of the subdivision to determine the height the rectangles.

All that's left to do now is to simply calculate the areas of the each of the rectangles. And add them up.

the base of each of the rectangle is \Delta{x}=0.5

and the height is determined in the table above.

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\text{Area}\,=0.5(12.25+16+20.25+25)

\text{Area}\,=36.75

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2 years ago
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