Answer:
The resulting, needed force for equilibrium is a reaction from a support, located at 2.57 meters from the heavy end. It is vertical, possitive (upwards) and 700 N.
Explanation:
This is a horizontal bar.
For transitional equilibrium, we just need a force opposed to its weight, thus vertical and possitive (ascendent). Its magnitude is the sum of the two weights, 400+300 = 700 N, since weight, as gravity is vertical and negative.
Now, the tricky part is the point of application, which involves rotational equilibrium. But this is quite simple if we write down an equation for dynamic momentum with respect to the heavy end (not the light end where the additional weight is placed). The condition is that the sum of momenta with respect to this (any) point of the solid bar is zero:
Where momenta from weights are possitive and the opposed force creates an oppossed momentum, then a negative term. Solving our unknown d:
So, the resulting force is a reaction from a support, located at 2.57 meters from the heavy end (the one opposed to the added weight end).
Explanation:
Force Description
1. 
It is also known as the weight of an object. It is the force that is exerted on an object due to its mass
2. 
It is force which is exerted by a push or a pull on an object. It is also known as applied force.
3. 
It is known as resistive force. It opposes the motion of an object.
4. 
It is the force which is at a right angle to the surface or perpendicular to the surface.
Explanation:
It is given that,
Mass of bumper car, m₁ = 202 kg
Initial speed of the bumper car, u₁ = 8.5 m/s
Mass of the other car, m₂ = 355 kg
Initial velocity of the other car is 0 as it at rest, u₂ = 0
Final velocity of the other car after collision, v₂ = 5.8 m/s
Let p₁ is momentum of of 202 kg car, p₁ = m₁v₁
Using the conservation of linear momentum as :
p₁ = m₁v₁ = -342 kg-m/s
So, the momentum of the 202 kg car afterwards is 342 kg-m/s. Hence, this is the required solution.
<u>Answer</u>
Gravitational force
<u>Explanation</u>
Gravitational force is the force of attraction between two bodies of a given masses. It is calculated as follows:
Gravitational force = GM₁M₂/r²
From the formula it can be seen that gravitational force is inversely proportional to the r where are is the distance between the two bodies.
When the distance increases the gravitational force decreases.
