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2 years ago

A 10 N force is applied to a hockey puck over a period of 0.1 s. What is the change in momentum of the hockey puck?

Physics

1 answer:

sergiy2304 [10]2 years ago

5 0

Answer:

$\Delta p = 1.0 \ \rm N.s.$

Explanation:

Given data:

Force, $F = 10 \ \rm N$

Time, $t = 0.1 \ s$

The change in momentum is equal to the impulse acting on the hockey puck. Moreover, the impulse is the product of the applied force and the time interval.

Thus, the change in momentum can be given as,

$\Delta p = F \times t$

$\Delta p = 10 \ \rm N \times 0.1 \ s$

$\Delta p = 1.0 \ \rm N.s.$

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