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oksian1 [2.3K]
2 years ago
12

Roundup, an herbicide manufactured by Monsanto, has the formula C₃H₈NO₅P. How many moles of molecules are there in a 304.3-g sam

ple of Roundup?
Chemistry
1 answer:
jekas [21]2 years ago
7 0
<span>The molar mass is 169.09

304.3g/169.09g = 1.799mol which rounds to 1.800 mol</span>
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How many g i2 should be added to 750g ccl4 to prepare a 0.200m solution?
vesna_86 [32]
<span>There are a number of ways to express concentration of a solution. This includes molality. Molality is expressed as the number of moles of solute per mass of the solvent. We calculate as follows:

0.200 mol I2 / kg CCl4 ( .750 kg CCl4 ) ( 253.809 g I2 / mol I2) = 38.07 g I2 needed

Hope this helps.

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Determine the number of moles in 4.21 x 10^23 molecules of CaCl2
Paha777 [63]
<h3>Answer:</h3>

0.699 mole CaCl₂

<h3>Explanation:</h3>

To get the number of moles we use the Avogadro's number.

Avogadro's number is 6.022 x 10^23.

But, 1 mole of a compound contains  6.022 x 10^23 molecules

In this case;

we are given 4.21 × 10^23 molecules of CaCl₂

Therefore, to get the number of moles

Moles = Number of molecules ÷ Avogadro's constant

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Hence, the number of moles is 0.699 mole of CaCl₂

7 0
2 years ago
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H2 ratio = [4 g / 2 g/mol] / 1

H2 ratio = 2

 

<span>We can see that PF3 has the lowest ratio, so it is the limiting reactant.</span>

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