Answer:
Equation C follows the law of conservation
GaF3 + 3Cs → 3CsF + Ga
Explanation:
Step 1: Data given
The law of conservation of matter states that in any given system that is closed to the transfer of matter, the amount of matter in the system stays constant
. This means, in chemical reactions, the total mass of the products must equal the total mass of the reactants.
A
2K + Ca(NO3)2 → K(NO3) + Ca
In this equation, we have 2x K on the left side, but only 1x K on the right side (in KNO3). We have 2x NO3 on the left side (in Ca(NO3)2 ) but only 1x NO3 on the right side (in KNO3). The amount is not the same on both side, so <u>doesn't follow the law of conservation of matter</u>
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The correct equation would be 2K + Ca(NO3)2 → 2K(NO3) + Ca
B
C5H12 + 7O2 → 5CO2 + 6H2O
In this equation we have 14x O atoms on the left side, but 16x O atoms on the right side (10x O in 5CO2 and 6x O in 6H2O). This means we have more O- atoms in products than in the reactants. The amount is not the same on both side, so <u>doesn't follow the law of conservation of matter</u>
The correct equation would be C5H12 + 8O2 → 6H2O + 5CO2
C
GaF3 + 3Cs → 3CsF + Ga
In this equation we have the same amount in reactants as in products.
This equation f<u>ollows the law of conservation</u>
D
2VCl2 + H2 → 2HCl + V
On the left side we have 2x V (in 2VCl2), on the right side we have 1x V. The amount is not the same on both side, so <u>doesn't follow the law of conservation of matter</u>
The correct equation would be VCl2 + H2 → 2HCl + V
