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olya-2409 [2.1K]
2 years ago
11

A steel cylinder at sea level contains air at a high pressure. Attached to the tank are two gauges, one that reads absolute pres

sure and one that reads gauge pressure. The tank is then brought to the top of a mountain.
Which statement is true for the gauge that reads gauge pressure?

a. Both gauges will change by the same amount.
b. The pressure reading increases.
c. The pressure reading stays the same.
d. The pressure reading decreases.
Physics
2 answers:
Aleksandr [31]2 years ago
6 0

Answer:

B. The pressure reading increases.

Explanation:

Gas pressure is an absolute pressure and atmospheric pressure decreases as height with respect to sea level is increased. Gauge pressure is the difference between absolute pressure and atmospheric pressure. Therefore, absolute pressure remains the same and gauge pressure reading increases.

The correct answer is option B.

marishachu [46]2 years ago
3 0

Answer:

C) The pressure reading stays the same.

Explanation:

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Answer:

A is the correct answer.

Explanation:

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A front wheel drive car starts from rest and accelerates to the right. Knowing that the tires do not slip on the road, what is t
Korolek [52]

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static friction acting opposite to the direction of travel

Explanation:

Because the Frictional force of the front wheels act to oppose the spinning, so, For the front wheels to roll without slipping, the friction must be static friction pointing in the direction of travel of the car.

Explanation:

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2 years ago
a child hits a ball with a force of 350 N. (a) If the ball and bat are in contact for 0.12 is, what impulse does the ball receiv
Lina20 [59]

Explanation:

Given that,

Force with which a child hits a ball is 350 N

Time of contact is 0.12 s

We need to find the impulse received by the ball. The impulse delivered is given by :

J=F\times t\\\\J=350\times 0.12\\\\J=42\ N-m

So, the impulse is 42 N-m..

We know that he change in momentum is also equal to the impulse delivered.

So, impulse = 42 N-m and change in momentum =42 N-m.

7 0
2 years ago
The initial velocity of a 4.0-kg box is 11 m/s, due west. After the box slides 4.0 m horizontally, its speed is 1.5 m/s. Determi
ankoles [38]

Answer:

F = - 59.375 N

Explanation:

GIVEN DATA:

Initial velocity = 11 m/s

final velocity = 1.5 m/s

let force be F

work done =  mass* F = 4*F

we know that

Change in kinetic energy = work done

kinetic energy = = \frac{1}{2}*m*(v_{2}^{2}-v_{1}^{2})

kinetic energy = = \frac{1}{2}*4*(1.5^{2}-11^{2}) = -237.5 kg m/s2

-237.5 = 4*F

F = - 59.375 N

7 0
2 years ago
A ball of mass m is found to have a weight Wx on Planet X. Which of the following is a correct expression for the gravitational
Naya [18.7K]

Answer: B. The gravitational field strength of Planet X is Wx/m.

Explanation:

Weight is a force, and as we know by the second Newton's law:

F = m*a

Force equals mass times acceleration.

Then if the weight is:

Wx, and the mass is m, we have the equation:

Wx = m*a

Where in this case, a is the gravitational field strength.

Then, isolating a in that equation we get:

Wx/m = a

Then the correct option is:

B. The gravitational field strength of Planet X is Wx/m.

4 0
2 years ago
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