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chubhunter [2.5K]
2 years ago
3

Each 2.0-m length of a long cylinder (radius = 4.0 mm) has a charge of 4.0 nC distributed uniformly throughout its volume. What

is the magnitude of the electric field at a point 5.0 mm from the axis of the cylinder?
Physics
1 answer:
Vesnalui [34]2 years ago
7 0

Answer: 5618N/C

Explanation:

According to the question, for every 2m length of the cylinder, there is a total charge of 4.0nC (an equivalent of 4×10^(-9)C).

Therefore by comparison, for a 5mm (0.005m) length,

The quantity of charge distributed through out its volume would be

Quantity of charge(Q) =

(4nC × 0.005m)÷(2m)

The quantity of charge (Q) at this length is then 0.01nC or 1 × 10^(-11)C.

To evaluate the magnitude of electric field at a point, the formulae used is provided below:

E= kQ÷r²

However, in this case this in converted into an integral and evaluated over the radius of the cylinder.

Therefore,

E= (8.99×10^(9) Nm²/C²× 1×10^(-11)C) ÷ (0.004²)

Since radius(r)=4mm=0.004m.

E= 5618.75N/C.

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An automatic coffee maker uses a resistive heating element to boil the 2.4 kg of water that was poured into it at 21 °C. The cur
MariettaO [177]

Answer:

Explanation:

The expression for the calculation of the enthalpy change of a process is shown below as:-

\Delta H=m\times C\times \Delta T

Where,  

\Delta H

is the enthalpy change

m is the mass

C is the specific heat capacity

\Delta T

is the temperature change

Thus, given that:-

Mass of water = 2.4 kg

Specific heat = 4.18 J/g°C

\Delta T=100-21\ ^0C=79\ ^0C

So,  

\Delta H=2.4\times 4.18\times 79\ J=792.52\ kJ

Heat Supplied Q=VIt

where i=current

V=Voltage

8.5\times 120\times t=2.4\times 4186\times 79

t=778.10 s

 

6 0
2 years ago
A physician orders Humulin R 44 units and Humulin N 40 units qam and Humulin R 35 units ac evening meal subcutaneously. How many
jekas [21]

The question is incomplete, the concentration of qam and humulin is not given unless R is used concentration

Complete question:

A physician orders Humulin 50/50 44 units and Humulin N 40 units qam and Humulin R 35 units ac evening meal subcutaneously. How many total units of insulin are administered each morning?

Answer:

the total units of insulin admistered each morning

= 22 units of qam and humulin

Explanation:

given

44 units and Humnlin N

with concentration 50/100 = 1/2 = 0.5

∴ 44 × 0.5 ≈ 22 units in the morning

regular insulin administered each day

(22 + 35)units of qam and humulin

= 57units

5 0
2 years ago
What is the magnitude of the relative angle φ
melomori [17]

Complete question is;

A ski jumper travels down a slope and leaves the ski track moving in the horizontal direction with a speed of 24 m/s. The landing incline below her falls off with a slope of θ = 59◦ . The acceleration of gravity is 9.8 m/s².

What is the magnitude of the relative angle φ with which the ski jumper hits the slope? Answer in units of ◦

Answer:

14.08°

Explanation:

The time covered will be given by the formula;

t = (2V_x•tan θ)/g

t = (2 × 24 × tan 59)/9.8

t = 8.152 s

Now, the slope of the flight path at the point of impact will be given by the formula;

tan α = V_y/V_x

We are given V_x = 24 m/s

V_y will be gotten from the formula;

v = gt

Thus;

V_y = gt

V_y = 9.8 × (8.152) = 78.89 m/s

Thus;

tan α = 78.89/24

tan α = 3.2871

α = tan^(-1) 3.2871

α = 73.08°

Thus ;

Relative angle φ = α - θ = 73.08 - 59 = 14.08°

6 0
2 years ago
20 points please help!!
IgorC [24]

Answer:

Sample Response: If temperature and surface area increase, then the time it takes for sodium bicarbonate to completely dissolve will decrease, because increasing both factors increases the rate of a chemical reaction.

Explanation:

4 0
2 years ago
A microprocessor scans the status of an output I/O device every 20 ms. This is accomplished by means of a timer alerting the pro
Lerok [7]

Answer:

0.0000045 s

Explanation:

f = Frequency = 8 MHz

Clock cycle is given by

\dfrac{1}{f}=\dfrac{1}{8\times 10^6}=1.25\times 10^{-7}\ s

Time taken for 12 clock cycles

12\times 1.25\times 10^{-7}=0.0000015\ s

Time taken per instruction is 0.0000015 s

In reading and displaying information it requires 3 processes

1 for reading, 1 for searching and 1 for displaying.

3\times 0.0000015=0.0000045\ s

Time taken is 0.0000045 s

6 0
2 years ago
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