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kumpel [21]
2 years ago
4

A binary ionic compound is known to contain a cation with 51 protons and 48 electrons. The anion contains one-third the number o

f protons as the cation. The num- ber of electrons in the anion is equal to the number of protons plus 1. What is the formula of this compound? What is the name of this compound?
Chemistry
1 answer:
kirill115 [55]2 years ago
7 0

Answer:

The answer to your question is  Antimony chloride or Antimony trichloride

                                                      Formula   SbCl₃

Explanation:

Data

Cation                                   Anion

51 protons                             1/3 of the protons of the cation

48 electrons                          electrons = protons + 1

Process

1.- Look for the element that has an atomic number of 51

            Antimony = Sb

- It has 48 electrons, that means its charge is

            51 - 48 = 3

-Then, the formula of Antimony is

                                 Sb⁺³

2.- Divide 51 by 3

      51/3 = 17

-Look for the element with an atomic number of 17                  

-This element is Chlorine

                                Cl

-Calculate the charge of Chlorine

         17 - 18(17 + 1) = -1

-Then, the formula of chlorine is

                                 Cl⁻¹

3.- Write the formula of the compound

                               Sb⁺³ + Cl⁻¹  = SbCl₃

4.- Write the name of the compound.

This compound is a binary salt, so, it is called

                             Antimony chloride or Antimony trichloride

                                   

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his is the chemical formula for chromium(III) nitrate: . Calculate the mass percent of oxygen in chromium(III) nitrate. Round yo
Alinara [238K]

Answer:

\%\ Composition\ of\ iron=69.92\ \%

Explanation:

Percent composition is percentage by the mass of element present in the compound.

The formula for chromium(III) nitrate is Cr(NO_3)_3

Molar mass of chromium(III) nitrate = 238.011 g/mol

1 mole of chromium(III) nitrate contains 9 moles of oxygen

Molar mass of oxygen = 16 g/mol

So, Mass= Molar mass*Moles = 16*9 g = 144 g

\%\ Composition\ of\ iron=\frac{Mass_{iron}}{Total\ mass}\times 100

\%\ Composition\ of\ iron=\frac{144}{238.011}\times 100

\%\ Composition\ of\ iron=69.92\ \%

5 0
2 years ago
When 1.00 g of boron is burned in o2(g) to form b2o3(s), enough heat is generated to raise the temperature of 733 g of water fro
Bas_tet [7]
<span>Answer: For this problem, you would need to know the specific heat of water, that is, the amount of energy required to raise the temperature of 1 g of water by 1 degree C. The formula is q = c X m X delta T, where q is the specific heat of water, m is the mass and delta T is the change in temperature. If we look up the specific heat of water, we find it is 4.184 J/(g X degree C). The temperature of the water went up 20 degrees. 4.184 x 713 x 20.0 = 59700 J to 3 significant digits, or 59.7 kJ. Now, that is the energy to form B2O3 from 1 gram of boron. If we want kJ/mole, we need to do a little more work. To find the number of moles of Boron contained in 1 gram, we need to know the gram atomic mass of Boron, which is 10.811. Dividing 1 gram of boron by 10.811 gives us .0925 moles of boron. Since it takes 2 moles of boron to make 1 mole B2O3, we would divide the number of moles of boron by two to get the number of moles of B2O3. .0925/2 = .0462 moles...so you would divide the energy in KJ by the number of moles to get KJ/mole. 59.7/.0462 = 1290 KJ/mole.</span>
7 0
2 years ago
Given the following balanced reaction of hydrochloric acid and oxygen gas forming chlorine gas and water, how many grams of hydr
nadya68 [22]
The ratio of moles of reactants to moles of products can be seen from the coefficients in a balanced equation. In our case  4 moles of hydrochloric acid reacts with one mole of oxygen to produce two moles of chlorine and water.  So, <span> the ratio of moles of hydrochloric acid to moles of chlorine is 2:1. To determine the number moles, divide the mass by the mass of one mole. </span>
<span>Cl2 = 2 * 35.45 = 70.9 grams </span>
<span>Number of moles = 335 ÷ 70.9 </span>
<span>This is approximately 4.72 moles. The number of moles of hydrochloric acid is twice this number. </span>

<span>Mass of one mole = 1 + 35.46 = 36.45 grams </span>
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<span>This is approximately 344.45 grams. 
Correct answer A.</span>
6 0
2 years ago
Read 2 more answers
Find the concentration of H+ ions at a pH = 11 and pH = 6. Then divide the concentration of H+ ions at a pH = 11 by the of H+ io
andrew11 [14]

Explanation:

When pH of the solution is 11.

pH=-\log[H^+]

11=-\log[H^+]

[H^+]=1\times 10^{-11} M..(1)

At pH = 11, the concentration of H^+ ions is 1\times 10^{-11} M.

When the pH of the solution is 6.

pH=-\log[H^+]'

6=-\log[H^+]'

[H^+]'=1\times 10^{-6} M..(2)

At pH = 6, the concentration of H^+ ions is 1\times 10^{-6} M.

On dividing (1) by (2).

\frac{[H^+]}{[H^+]'}=\frac{1\times 10^{-11} M}{1\times 10^{-6}}=1\times 10^{-5}

The ratio of hydrogen ions in solution of pH equal to 11 to the solution of pH equal to 6 is 1\times 10^{-5}.

Difference between the H^+ ions at both pH:

1\times 10^{-6} M-1\times 10^{-11} M=9.99\time 10^{-7} M

This means that Hydrogen ions in a solution at pH = 7 has 9.99\time 10^{-7} M ions fewer than in a solution at a pH = 6

6 0
2 years ago
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An important reaction sequence in the industrial production of nitric acid is the following: N2(g) + 3H2(g) → 2NH3(g) 4NH3(g) +
frutty [35]

Answer:

The answer to your question is 50 moles of O₂

Explanation:

Balanced Chemical reactions

1.-                 N₂(g)  +  3H₂ (g)   ⇒   2NH₃ (g)

2.-                4NH₃ (g) + 5O₂(g)  ⇒  4NO (g)  +  6H₂O (l)

moles of N₂(g) = 20 moles

moles of O₂(g) = ?

Process

1.- Calculate the moles of NH₃

                     1 mol of N₂ ------------- 2 moles of NH₃

                   20 moles of N₂ ---------  x

                     x = (20 x 2) / 1

                     x = 40 moles of NH₃

2.- Calculate the moles of O₂

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               40 moles of NH₃ ------------  x

                    x = (40 x 5) / 4

                    x = 200 / 4

                    x = 50 moles of O₂

3 0
2 years ago
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