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Goryan [66]
2 years ago
3

Johnny was playing baseball with his friends and they noticed a bolt of lightning. They heard thunder seven seconds later. How f

ar away is the storm?
meters
Physics
2 answers:
Nostrana [21]2 years ago
6 0

Answer:

2380m

Explanation:

Given parameters:

Time taken to hear the sound after lightning  = 7s

Unknown:

Distance of the storm  = ?

Solution:

Light has been shown to travel faster than sound. To solve this problem,

                 Speed  = \frac{distance}{time taken}

Speed is the rate of change of distance with time

Distance  = speed x time taken

The speed of sound is given as 340m/s

Distance  = 340 x 7  = 2380m

Citrus2011 [14]2 years ago
5 0

Answer:

2,317 m

Explanation:

Just did this instruction on edgen :)

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Answer:

980 kJ

Explanation:

Work = change in energy

W = mgh

W = (1000 kg/m³ × 5.0 m³) (9.8 m/s²) (20 m)

W = 980,000 J

W = 980 kJ

The pump does 980 kJ of work.

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2 years ago
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Driving a motor vehicle requires many coordinated functions which are impacted by alcohol and other drugs
Anni [7]

I am assuming this is a true or false question, to which the answer would be True.

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2 years ago
If a rock is thrown upward on the planet mars with a velocity of 14 m/s, its height (in meters) after t seconds is given by h =
crimeas [40]

<u>Answer:</u>

 Velocity of rock after 2 seconds = 6.56 m/s

<u>Explanation:</u>

 We have equation of motion , s= ut+\frac{1}{2} at^2, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

Here height of rock in meters, h = 14t-1.86t^2

Comparing both the equations

    We will get initial velocity = 14 m/s(already given) and \frac{1}{2} a = -1.86

     So,  Acceleration, a = -3.72 m/s^2

 Now we have equation of motion, v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.

 When time is 2 seconds we need to find final velocity.

     v = 14 - 3.72 * 2 = 6.56 m/s.

  So, Velocity of rock after 2 seconds = 6.56 m/s  

6 0
2 years ago
When the balloon hits the ground, it rebounds slightly. What is the source of the energy for this rebound? A. When the balloon h
nevsk [136]

Answer:

The correct answer is c.    When the balloon hits the ground, the rubber envelope stretches, storing elastic potential energy; this elastic potential energy is converted to the gravitational potentiaL

Explanation:

Let's analyze the situation of the globe

When it touches the ground, the part that is in contact decreases its velocity to zero, but the upper part of the ball continues to move, which creates that the molecules approach slightly, if we approximate the spring links, a repulsive force is created that after all the particles reach zero speed. The force of the springs moves the ball up until the force decreases to zero.

We can relate this force of Hooke with an elastic energy

This energy can be stored in the deformation of the system, as elastic potential energy, which is subsequently transformed into gravitational potential energy when the balloon is lifted.

The correct answer is c

7 0
2 years ago
The initial velocity of a 4.0-kg box is 11 m/s, due west. After the box slides 4.0 m horizontally, its speed is 1.5 m/s. Determi
ankoles [38]

Answer:

F = - 59.375 N

Explanation:

GIVEN DATA:

Initial velocity = 11 m/s

final velocity = 1.5 m/s

let force be F

work done =  mass* F = 4*F

we know that

Change in kinetic energy = work done

kinetic energy = = \frac{1}{2}*m*(v_{2}^{2}-v_{1}^{2})

kinetic energy = = \frac{1}{2}*4*(1.5^{2}-11^{2}) = -237.5 kg m/s2

-237.5 = 4*F

F = - 59.375 N

7 0
2 years ago
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