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iogann1982 [59]

2 years ago

13

Ethan rollerbladed a total of 623 \text{ km}623 km623, start text, space, k, m, end text over ddd days. He rollerbladed the same

distance each day. How many kilometers did Ethan rollerblade each day?

1 answer:

Sever21 [200]2 years ago

5 0

Answer:

Ethan rollerbladed each day $\frac{623}{d}$ kilometers.

Step-by-step explanation:

Given:

Ethan rollerbladed a total of 623 km over d days.

Now, to find the kilometers Ethan rollerblade each day.

Total number of distance rollerbladed = 623 km.

Total number of days = $d.$

<u><em>As, Ethan rollerbladed each day the same distance.</em></u>

Now, to get the distance Ethan rollerbladed in each day we divide total number of distance rollerbladed by total number of days:

$Ethan\ rollerbladed\ each\ day\ =\ \frac{Total\ number\ of\ distance\ rollerbladed}{Total\ number\ of\ days}$

$Ethan\ rollerbladed\ each\ day\ =\ \frac{623}{d}$

Therefore, Ethan rollerbladed each day $\frac{623}{d}$ kilometers.

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The product of two numbers is 450. the first number is half the second number. which equation can be used to find x, the greater

kow [346]

X*y = 450
y = 1/2x

x(1/2x) = 450
1/2x^2 = 450
x^2 = 450 * 2
x^2 = 900
x = sqrt 900
x = 30

y = 1/2(30)
y = 15

so ur numbers are : x = 30 and y = 15...but I am not sure of ur answer choices.

5 0

2 years ago

Read 2 more answers

A pendulum is set swinging. its first oscillation is through 30 and each succeeding oscillation is through 95% of the angle of t

Marat540 [252]

<u>Answer-</u>

<em>After 76 swings</em><em> the angle through which it swings less than 1°</em>

<u>Solution-</u>

From the question,

Angle of the first of swing = 30° and then each succeeding oscillation is through 95% of the angle of the one before it.

So the angle of the second swing = $(30\times \frac{95}{100})^{\circ}$

Then the angle of third swing = $(30\times (\frac{95}{100})^2)^{\circ}$

So, this follows a Geometric Progression.

$(30,\ 30\cdot \frac{95}{100},\ 30\cdot (\frac{95}{100})^2............,0)$

a = The initial term = 30

r = Common ratio = $\frac{95}{100}$

As we have to find the number swings when the angle swept by the pendulum is less than 1°.

So we have the nth number is the series as 1, applying the formula

$T_n=ar^{n-1}$

Putting the values,

$\Rightarrow 1=30(\frac{95}{100})^{n-1}$

$\Rightarrow \frac{1}{30} =(\frac{95}{100})^{n-1}$

Taking logarithm of both sides,

$\Rightarrow \log \frac{1}{30} =\log (\frac{95}{100})^{n-1}$

$\Rightarrow \log \frac{1}{30} =(n-1)\log (\frac{95}{100})$

$\Rightarrow -1.5=(n-1)(-0.02)$

$\Rightarrow 1.5=(n-1)(0.02)$

$\Rightarrow n-1=\dfrac{1.5}{0.02}$

$\Rightarrow n-1=75$

$\Rightarrow n=76$

Therefore, after 76 swings the angle through which it swings less than 1°

8 0

2 years ago

The table shows the concentration of a reactant in the reaction mixture over a period of time.

saveliy_v [14]

<h3>Option C</h3><h3>The average rate of the reaction over the entire course of the reaction is: $2.0 \times 10^{-3}$ </h3>

<em><u>Solution:</u></em>

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$Average\ rate = \frac{ \triangle c }{\triangle t }$

The concentration of the reactants changes 1.8 M to 0.6 M

here, the time interval given is 0 to 580 sec

Therefore,

$Average\ rate = \frac{1.8-0.6}{580} \\\\Average\ rate = \frac{1.2}{580} \\\\Average\ rate \approx 2.0 \times 10^{-3}$

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5 0

2 years ago

the population of Ketcham high school has been decreasing by 5 % per year.if it's population is currently 2600 which of the foll

kap26 [50]

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6 0

2 years ago

What is the rule used to transform ΔABC to its image?

Allushta [10]

Answer:

D

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That is the x- coordinate remains unchanged while the y- coordinate is the negative of the original y- coordinate.

Given

A(- 3, 5 ) → A'(- 3, - 5 )

B(2, 8 ) → B'(2, - 8)

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6 0

2 years ago