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Igoryamba
2 years ago
15

H(x)= 8 1 ​ x 3 −x 2 h, left parenthesis, x, right parenthesis, equals, start fraction, 1, divided by, 8, end fraction, x, cubed

, minus, x, squared What is the average rate of change of h hh over the interval − 2 ≤ x ≤ 2 −2≤x≤2minus, 2, is less than or equal to, x, is less than or equal to, 2?
Mathematics
1 answer:
otez555 [7]2 years ago
4 0

Answer:

m = 324

Step-by-step explanation:

The average rate of change is:

m = \frac{h(2)-h(-2)}{2 - (-2)}

h(-2) = 81\cdot (-2)^{3}-(-2)^{2}

h(-2) = -652

h(2) = 81\cdot (2)^{3}-(2)^{2}

h(2) = 644

m = \frac{644-(-652)}{2-(-2)}

m = 324

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The question is missing the figure. So, it is attached below.

Answer:

Area of the shaded sector is <u>144π units squared</u>.

Step-by-step explanation:

Given:

Central angle of the sector is, \theta=\frac{8\pi}{9}\ rad

Radius of the circle is, R=18\ units

We know that, area of a sector of a circle of radius 'R' and central angle \theta is given as:

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Plug in \theta=\frac{8\pi}{9},R=18. This gives,

A=\frac{1}{2}\times (18)^2\times \frac{8\pi}{9}\\\\A=(\frac{324\times 4}{9})\pi\\\\A=(36\times 4)\pi\\\\A=144\pi\ units^2

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