This is a combinations problem.
The total number of possible 2-item combinations is (1000 choose 2)
The number of 2-defective combinations is (300 choose 2)
The probability =
As IQ scores for extensive populaces are focused at 100, the mean = 100.
There ought to be around half scores above or underneath the mean score since mean and middle is about a similar when the populace is substantial.
P(x > 100) = P( z> (100 - 100)/sd ) = P(z > 0)= 0.5
The number of the student who has scored over 100 = 0.5 x 78 = 39 Therefore the answer is 39 students.
Sketch the two quadrilaterals and label them as shown in the figure below.
Let x = length of the 4th side of ABCD.
Because ABCD ~ EFGH, therefore
x/5 = 14/6
That is,
x = (5/6)*14 = 11.67 ft
Answer: D. 11.7 ft