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riadik2000 [5.3K]
2 years ago
5

Find an explicit formula for the arithmetic sequence -5,13,31,49,...−5,13,31,49,...minus, 5, comma, 13, comma, 31, comma, 49, co

mma, point, point, point.
b(n)=b(n)=b, left parenthesis, n, right parenthesis, equals
Mathematics
1 answer:
dolphi86 [110]2 years ago
4 0

Answer:

aₙ = a₁ + (n-1) * 18        a₁ = -5

Step-by-step explanation:

aₙ = a₁ + (n-1) * d            a₁ = -5     d = 13 - (-5) = 18

a₂ = -5 + (2 - 1) * 18 = -5 + 18 = 13

a₃ = -5 + (3 - 1) * 18 = -5 + 36 = 31

a₄ = -5 + (4 - 1) * 18 = -5 + 54 = 49

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A fruit stand has to decide what to charge for their produce. They need \$5.30$5.30dollar sign, 5, point, 30 for 111 apple and 1
allochka39001 [22]

Answer:

111 apples cost $3.30 and 111 oranges cost $2 (1 apple costs nearly $0.03 and 1 orange costs nearly $0.02)

Step-by-step explanation:

Let the price of 111 apples be $x and the price of 111 oranges be $y.

1. 111 apples and 111 oranges cost $5.30, thus

x+y=5.30

2. 111 apples and 222 oranges cost $7.30, then

x+2y=7.30

Subtract the first equation from the second:

x+2y-x-y=7.30-5.30

y=2

Substitute it into the first equation:

x+2=5.30

x=3.30

111 apples cost $3.30 and 111 oranges cost $2 (1 apple costs nearly $0.03 and 1 orange costs nearly $0.02)

3 0
2 years ago
Read 2 more answers
Evaluate3|2+5|+2|3−2|+ 43; = −1
Stels [109]

Answer:

yes

Step-by-step explanation:

what you did ias correrct

7 0
2 years ago
In your sock drawer you have 5 blue, 7 gray, and 2 black socks. Half asleep one morning you grab 2 socks at random and put them
pentagon [3]

The question is incomplete! The complete question along with answers and explanation is provided below!

In your sock drawer you have 5 blue, 7 gray, and 2 black socks. Half asleep one morning you grab 2 socks at random and put them on. Find the probability you end up wearing the following socks. (Round your answers to four decimal places.)

a) 2 blue socks

b) no gray socks

c) at least 1 black sock

d) a green sock

e) matching socks

Answer:

a) P(2 blue socks) = 0.1099 = 10.99%

b) P(no gray socks) = 0.2307 = 23.07%

c) P(at least 1 Black sock) = 0.2748 = 27.48%

d) P(green sock) = 0%

e) P(Matching socks) = 0.3516 = 35.16%

Step-by-step explanation:

Given Information:

5 Blue socks

7 Gray socks

2 black socks

Total socks = 5 + 7 + 2 = 14

a) The probability of wearing 2 blue socks

P(2 blue socks) = P(B1 and B2)

P(B1) = no. of blue socks/total no. of socks

P(B1) = 5/14 = 0.3571

Now there are 4 blue socks remaining and total 13 socks remaining

P(B2|B1) = 4/13 = 0.3077

P(B1 and B2) = 0.3571*0.3077 = 0.1099 = 10.99%

b) The probability of wearing no gray socks

5 Blue socks + 2 black socks = 7 socks are not gray

P(no gray socks) = P(Not G1 and Not G2)

P(Not G1) = no. socks that are not grey/ total no. of socks

P(Not G1) = 7/14 = 0.5

Now there are 6 socks remaining that are not gray and total 13 socks remaining

P(Not G2 | Not G1) = 6/13 = 0.4615

P(Not G1 and Not G2) = 0.5*0.4615 = 0.2307 = 23.07%

c) The probability of wearing at least 1 black sock

5 Blue socks + 7 Gray socks = 12 socks are not black

P(at least 1 Black) = 1 - P(Not B1 and Not B2)

P(Not B1) = no. socks that are not black/ total no. of socks

P(Not B1) = 12/14 = 0.8571

Now there are 11 socks remaining that are not black and total 13 socks remaining

P(Not B2 | Not B1) = 11/13 = 0.8461

P( Not B1 and Not B2) = 0.8571*0.8461 = 0.7252

P(at least 1 Black) = 1 - P( Not B1 and Not B2)

P(at least 1 Black) = 1 - 0.7252 = 0.2748 = 27.48%

d) The probability of wearing a green sock

There are 0 green socks, therefore

P(Green) = 0/14 = 0%

e) The probability of wearing matching socks

P(Matching socks) = P(2 Blue socks) + P(2 Gray socks) + P(2 Black socks)

P(2 Blue socks) already calculated in part a

P(2 Blue socks) = P(B1 and B2) = 0.1099

For Gray socks

P(G1) = no. of gray socks/ total no. of socks

P(G1) = 7/14 = 0.5

Now there are 6 gray socks remaining and total 13 socks remaining

P(G2 | G1) = 6/13 = 0.4615

P(2 Gray socks) = P(G1 and G2) = 0.5*0.4615 = 0.2307

For Black socks

P(B1) = no. of black socks/ total no. of socks

P(B1) = 2/14 = 0.1428

Now there is 1 black sock remaining and total 13 socks remaining

P(B2 | B1) = 1/13 = 0.0769

P(2 Black socks) = P(B1 and B2) = 0.1428*0.0769 = 0.0110

P(Matching socks) = P(2 Blue socks) + P(2 Gray socks) + P(2 Black socks)

P(Matching socks) = 0.1099 + 0.2307 + 0.0110 = 0.3516 = 35.16%

7 0
2 years ago
Write an equation perpendicular to x-4y=20 that passes through the point 2,-5
marshall27 [118]

Answer:

  4x +y = 3

Step-by-step explanation:

Perpendicular lines have slopes that are the negative reciprocals of one another. When the equation of the line is written in standard form like this, the equation of the perpendicular line can be written by swapping the x- and y-coefficients and negating one of them. Doing this much would give you ...

  4x +y = (constant)

Note that we have chosen to make the equation read 4x+y, not -4x-y. The reason is that "standard form" requires the leading coefficient to be positive.

Now, you just need to make sure the constant is appropriate for the point you want the line to go through. So, it needs to be ...

  4(2) +(-5) = constant = 3

The line of interest has equation ...

  4x + y = 3

3 0
2 years ago
Perform the indicated operation. (y4 - 1) ÷ (y + 1)
olya-2409 [2.1K]

Factorize the numerator as a difference of squares:

y^4-1=(y^2-1)(y^2+1)=(y-1)(y+1)(y^2+1)

Then if y\neq-1, the y+1 factors will cancel:

\dfrac{y^4-1}{y+1}=(y-1)(y^2+1)=y^3-y^2+y-1

so the answer is B.

8 0
2 years ago
Read 2 more answers
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