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Harman [31]
2 years ago
5

How many moles of carbon are in 7.87x10' carbon atoms?

Chemistry
1 answer:
larisa [96]2 years ago
6 0

Answer:

1.306 moles of C

Explanation:

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What type of star has an absolute brightness of 1 and a surface temperature around 7,500 °C?
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<span>A dim white dwarf star, this is a star with a similar mass to earth. This star has no further fusion reactions at it's core. After this type of star has used up all of it's energy it will become a black dwarf star. Usually they are composed of oxygen and carbon. Sirius a and b are both white dwarf stars that orbit each other.</span>
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2 years ago
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a 9.84 ounces ingot of unknown metal is heated from 73.2 degrees fahrenheit - 191.2 degrees fahrenheit this requires 3.912 calor
Gekata [30.6K]

The SI unit of specific heat is J per gram per degree Celsius. Thus it follows that specific heat could be calculated in this way:

Specific Heat = Energy / (mass x change in temperature)

Thus,

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2 years ago
What is the value of Keq for the reaction expressed in scientific notation? 2.1 x 10-2 2.1 x 102 1.2 x 103 1.2 x 10-3
Lady_Fox [76]

Complete question:

Consider the reaction.

At equilibrium at 600 K, the concentrations are as follows.

2HF -----> H₂ + F₂

[HF] = 5.82 x 10-2 M

[H2] = 8.4 x 10-3 M

[F2] = 8.4 x 10-3 M

What is the value of Keq for the reaction expressed in scientific notation?

2.1 x 10-2

2.1 x 102

1.2 x 103

1.2 x 10-3

Answer:

2.1 × 10^-2

Explanation:

Kequilibrum(Keq) = product/reactant

Equation for the reaction :

2HF -----> H₂ + F₂

Therefore,

Keq = [H2][F2] / [HF]^2

Keq = [8.4 x 10-3][8.4 x 10-3] / [5.82 x 10-2]^2

Keq = [70.56 × 10^(-3 + - 3)]/[33.8724 × 10^(-2×2)]

Keq = [70.56 × 10^-6] / [33.8724 × 10^-4]

Keq = 2.0665 × 10^(-6 - (-4))

Keq = 2.0665 × 10^(-6 + 4)

Keq = 2.1 × 10^-2

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2 years ago
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Does oxygen have a greater mass than chlorine
rjkz [21]
Atomic oxygen does not have a greater atomic mass than chlorine, nor does molecular oxygen.

Hope this help...


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What should be done if particles of precipitate appear in the filtrate?
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