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2 years ago

4

A woman is deciding between three alarm systems to install in her home. Each alarm system produces a wave with a different wavel

ength and decibel level, as shown in the following table.
1st number: Wavelength (cm)

2nd number: Decibels (dB)

Alarm A

8

100

Alarm B

32

80

Alarm C

128

60

If the woman wants the alarm with the lowest pitch, which alarm should she choose? Explain your answer.

Based on the data in the table, which alarm produces sound waves with the greatest amplitude? Explain your answer.

2 answers:

marissa [1.9K]2 years ago

6 0

Answer:

C

Explanation:

its most likely going to be C

I THNK

w(ﾟДﾟ)w

statuscvo [17]2 years ago

3 0

Answer:

C?

Explanation:

I think C is what it’s asking for in amplitude

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Two lasers, one red (with wavelength 633.0 nm) and the other green (with wavelength 532.0 nm), are mounted behind a 0.150-mm sli

Orlov [11]

Answer:

a.3.20m

b.0.45cm

Explanation:

a. Equation for minima is defined as: $sin \theta=\frac{m\lambda}{\alpha}$

Given $m=3$ , $\lambda=6.33\times 10^-^7$ and $\alpha=0.00015$ :

#Substitute our variable values in the minima equation to obtain $\theta$ :

$\theta=sin^-^1 (\frac{3\times 6.33\times 10^-^7}{0.00015})\\\\\theta=0.01266rad$

#draw a triangle to find the relationship between $\theta, y \$ and $L$ .

$tan(\theta)=y/L$ #where $y=4.05cm$

$L=y/tan(\theta)=3.20$

Hence the screen is 3.20m from the split.

b. To find the closest minima for green(the fourth min will give you the smallest distance)

#Like with a above, the minima equation will be defined as:

$sin \theta=\frac{m\lambda}{\alpha}$ , where $m=4$ given that it's the minima with the smallest distance.

$sin \theta=\frac{4\lambda}{\alpha}\\\theta=sin^-^1 (\frac{4\times 6.33\times 10^-^7}{0.00015})\\\\\theta=0.01688rad$

#we then use $tan(\theta)=y/L$ to calculate $L$ =4.5cm

Then from the equation subtract $y_3$ from $y$ :

$4.50cm-4.05cm=0.45cm$

Hence, the distance $\bigtriangleup y$ is 0.45cm

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2 years ago

A truck pulled a car of 2,350 kg a distance of 25 meters. If the car accelerates from 3 m/s to 6 m/s, whats the average force ex

faust18 [17]

Answer:

1,269 N

Explanation:

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1. When the fission of uranium-235 is carried out, about 0.1 percent of the mass of the reactants is lost during the reaction. W

DerKrebs [107]

The correct answer to the question is that the lost mass has been converted into energy.

EXPLANATION:

From Einstein's theory, we know that energy and mass are inter convertible .

When some amount of mass is lost, same amount of energy equivalent to mass is produced.

Let us consider m is the mass lost during any reaction. Hence, the amount of energy produced will be-

Energy E = $mc^2$

Here, c is the velocity of light i.e c = $3\times 10^8\ m/s$

As per the question, uranium-235 undergoes fission. The amount of mass defect is 0.1 %.

The mass defect is defined as the difference between mass of reactants and products. During the fission, energy is produced.

The energy produced in this reaction is nothing else than the energy equivalent to mass defect. Approximately 199.5 Mev of energy equivalent to this mass defect is produced in this reaction.

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A man is dragging a trunk up the loading ramp of a mover’s truck. The ramp has a slope angle of 20.0°, and the man pulls upward

AleksandrR [38]

Answer:

(a) 104 N

(b) 52 N

Explanation:

Given Data

Angle of inclination of the ramp: 20°

F makes an angle of 30° with the ramp

The component of F parallel to the ramp is Fx = 90 N.

The component of F perpendicular to the ramp is Fy.

(a)

Let the +x-direction be up the incline and the +y-direction by the perpendicular to the surface of the incline.

Resolve F into its x-component from Pythagorean theorem:

Fx=Fcos30°

Solve for F:

F= Fx/cos30°

Substitute for Fx from given data:

Fx=90 N/cos30°

=104 N

(b) Resolve r into its y-component from Pythagorean theorem:

Fy = Fsin 30°

Substitute for F from part (a):

Fy = (104 N) (sin 30°)

= 52 N

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A storage tank holds methane at 120 K, with a quality of 25 %, and it warms up by 5°C per hour due to a failure in the refrigera

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One of the fundamental pillars to solve this problem is the use of thermodynamic tables to be able to find the values of the specific volume of saturated liquid and evaporation. We will be guided by the table B.7.1 'Saturated Methane' from which we will obtain the properties of this gas at the given temperature. Later considering the isobaric process we will calculate with that volume the properties in state two. Finally we will calculate the times through the differences of the temperatures and reasons of change of heat.

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$T_1 = 120K$

$p_1 = 191.6kPa$

$v_f = 0.002439m^3/kg$

$v_{fg} = 0.30367 m^3/kg$

Calculate the specific volume of the methane at state 1

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$v_1 = 0.002439+ (0.25)(0.30367)$

$v_1 = 0.0783m^3/kg$

Assume the tank is rigid, specific volume remains constant

$v_2 = v_1$

$v_2 = 0.0783m^3/kg$

Now from the same table we can obtain the properties,

At $v_g = 0.0783m^3/kg$

$T_2 = 145K$

$p_2 = 823.7kPa$

We can calculate the time taken for the methane to become a single phase

$t = \frac{T_2-T_1}{\dot{T}}$

Here

$T_1 =$ Initial temperature of Methane

$\dot{T} =$ Warming rate

Replacing

$t = \frac{(145-273)-(120-273)}{5}$

$t = \frac{25}{5}$

$t = 5hr$

Therefore the time taken for the methane to become a single phase is 5hr

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