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2 years ago

If a heat engine takes in 4565 kJ and gives up 2955 kJ during one cycle, what is the engine’s efficiency?

Physics

1 answer:

vodomira [7]2 years ago

5 0

The engine efficiency is 64.73 %

<u>Explanation:</u>

Given data

To find the engine’s efficiency we have the formula,

Energy input- 4565 KJ

Energy output - 2955KJ

Efficiency= energy output/ energy input ×100%

=2955/4565

=0.6473 ×100

η =64.73 %

The engine efficiency is 64.73 %

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Answer:

40.13491 m/s

Explanation:

$v_r$ = My speed = 35 m/s

v = Speed of sound in air = 343 Hz

$v_s$ = Speed of the police car

When the car is approaching

$f=f'\dfrac{v-v_r}{v-v_s}\\\Rightarrow 1340=f'\dfrac{343-35}{343-v_s}$

When the car is receding

$f=f'\dfrac{v+v_r}{v+v_s}\\\Rightarrow 1300=f'\dfrac{343+35}{343+v_s}$

Dividing the equations

$\dfrac{1340}{1300}=\dfrac{f'\dfrac{343-35}{343-v_s}}{f'\dfrac{343+35}{343+v_s}}\\\Rightarrow \dfrac{1340}{1300}=\dfrac{22\left(v_s+343\right)}{27\left(-v_s+343\right)}\\\Rightarrow -36180v_s+12409740-12409740=28600v_s+9809800-12409740\\\Rightarrow \frac{-64780v_s}{-64780}=\frac{-2599940}{-64780}\\\Rightarrow v_s=\frac{129997}{3239}\\\Rightarrow v_s=40.13491\ m/s$

The speed of the police car is 40.13491 m/s

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2 years ago

What is the direction of the current in the loop as the loop rotates clockwise through the magnetic field from as viewed from th

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Answer:

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A machine is currently set to a feed rate of 5.921 inches per minute (IPM). Te machinist changes this setting to 6.088 IPM. By h

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Answer:

By 16.7% or 0.167 IPM

Explanation:

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2 years ago

A 38 kg crate rests on a floor. A horizontal pulling force of 170 N is needed to start the crate

Mandarinka [93]

Answer:

0.456033049

Explanation:

$F=\mu N$ where N=mg hence

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Making $\mu$ the subject we obtain

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