What is the volume in mL of 3.59 g CO2 of gas at 2.09 atm and -14 oC?
1 answer:
800 ml is the volume in mL of 3.59 g CO2 of gas at 2.09 atm and -14°C.
Explanation:
Data given:
mass of the carbon dioxide gas = 3.59
pressure of the carbon dioxide gas = 2.09 atm
temperature of the carbon dioxide gas = -14 degrees OR 273.15 +(-14) = 259.15 K
atomic mass of carbon dioxide =44.01 grams/mole
R = 0.0821 L.atm/mole K
volume occupied by the gas =?
number of moles of CO2 =
number of moles =
number of moles of carbon dioxide gas = 0.081 moles
from ideal gas law
PV = nRT
V =
V = 0.80 L is the volume of carbon dioxide gas
volume in ml = 0.8 x 1000
volume in ml= 800 ml
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2,4,4-trimethyl-2-pentene yields mixture of and
Explanation:
In ozonolysis (hydrolysis step involve a reducing agent such as Zn, etc.), a pi bond is broken to form ketone/aldehyde.
Ketone is formed from di-substituted side of double bond and aldehyde is formed from mono-substituted side of double bond.
Ozoznolysis involves two consecutive steps : (1) formation of ozonide, (2) hydrolysis of ozonide.
Hydrolysis can be done with/without using reducing agent. Carboxylic acid/carbon dioxide/ketone is produced when hydrolysis is done without using reducing agent.
Here, 2,4,4-trimethyl-2-pentene yields mixture of and
Reaction steps are shown below.
