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hjlf
2 years ago
3

A 1.5 mol sample of radon gas has a volume of 21.0L at 33°C.

Chemistry
1 answer:
PIT_PIT [208]2 years ago
6 0

Answer:

The correct answer is D) 1.8 atm.

Explanation:

We use the ideal gas formula (PV= nRT). We first convert the unit of temperature in degrees Celsius to Kelvin. We use the ideal gas constant R = 0.082 l atm / K mol. We solve P:

273K =0°C ---> 33°C= 273 + 33=306 K

PV= nRT ----> P =(nRT)/ V

P= ( 1,5 mol x 0.082 l atm / K mol x 306 K)/ 21,0 L

<em>P= 1,79 atm</em>

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