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oksano4ka [1.4K]
2 years ago
7

The name of CH3CH2CH2CH2CH2CONH2 is: hexanamide butanamide pentanamide O heptanamide

Chemistry
1 answer:
pickupchik [31]2 years ago
6 0

Answer:

hexanamide.

Explanation:

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Calculate the hydrogen ion concentration in a solution of fruit juice having a pH of 4.25.
Airida [17]

Answer:

<h3>The answer is option B</h3>

Explanation:

The pH of a solution can be found by using the formula

pH = - log [ H+ ]

To find the hydrogen ion concentration substitute the pH into the above formula and solve for the [ H+ ]

From the question

pH = 4.25

So we have

4.25 = - log [ H+ ]

<u>Find the antilog of both sides</u>

That's

<h3>[ H+ ] =  {10}^{ - 4.25}</h3>

We have the final answer as

<h2>[ H+ ] = 5.6 \times  {10}^{ - 5}  \: M</h2>

Hope this helps you

3 0
2 years ago
Which phrase best describes a chemical reaction? A. mixing two substances B. the combustion of a substance C. forming or breakin
nirvana33 [79]
The answer for the problem is C
6 0
2 years ago
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How many atoms of S are in 98.0 grams of hydrosulfuric acid?
noname [10]
<h2>Answer:6.022\times 10^{23}</h2>

Explanation:

The formula for sulphuric acid is H_{2}SO_{4}.

Molecular mass of sulphuric acid is 2(2)+32+16(4)=98g

given weight=98g

Number of moles of sulphuric acid given is \frac{\text{given weight}}{molar mass}=\frac{98}{98}=1

The formula indicates that one mole of H_{2}SO_{4} contains 2 moles of H atoms,1 mole of S atoms,4 moles of O atoms.

So,the compound contains 1 mole of sulphur atoms.

1 mole of sulphur has 6.022\times 10^{23} atoms

7 0
2 years ago
Adhesion describes water's attraction to _____. other water molecules other substances hydrogen molecules acids and bases
Yuliya22 [10]
Adhesion describes water's attraction to other substances. 

The term Adhesion refers to the tendency of particles or surfaces which are not similar to cling to one another. So basically, the adhesion occurs in water when the water is attracted or cling to other substance not similar to water.
4 0
2 years ago
Read 2 more answers
Iodine-131 has a half-life of 8.10 days. In how many days will 50 grams of Iodine-131 decay to one-eighth of its original amount
shtirl [24]
What you need to do is find 1/8 of 50
you can just divide 50 by 8 to get 6.25
so now you have to find how many days it will take till there are 6.25 grams of iodine left
every 8.1 days its mass is split in half 
so start splitting it in half and every time you do, you add 8.1 days
50/2 =25                                               8.1
25/2 =12.5                                        +  8.1
12.5/2= 6.25                                      +8.1
now you have reached 1/8 of the original amount of Iodine-131
so to find how long it took just add 8.1+8.1+8.1
(this is the same as 8.1x3)
which equals 24.3
it will take 24.3 days for Iodine 131 to decay to 1/8  of its original mass.

(good luck on the regent if thats what your studying for :)

5 0
2 years ago
Read 2 more answers
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