Answer:
a. both temperature changes will be the same
Explanation:
When sodium hydroxide (NaOH) is dissolved in water, a determined amount is released to the solution following the equation:
Q = m×C×ΔT
<em>Where Q is the heat released, m is the mass of the solution, C is the specific heat and ΔH is change in temperature.</em>
Specific heat of both solutions is the same (Because the solutions are in fact the same). Specific heat = C.
m is mass of solutions: 102g for experiment 1 and 204g for experiment 2.
And Q is the heat released: If 2g release X heat, 4g release 2X.
Thus, ΔT in the experiments is:
Experiment 1:
X / 102C = ΔT
Experiment 2:
2X / 204C = ΔT
X / 102C = ΔT
That means,
<h3>a. both temperature changes will be the same</h3>
Answer:
A description of the experiment the chemicals were used for.
Explanation:
A chemical waste label is required to provide information about any hazardous waste present in the container. Some details are mandatory to mention of the chemical waste label to prevent any accident while doing the experiment, that includes:
- Chemical compound's name present in the container.
- Composition and physical state of the waste.
- Hazardous properties of the waste.
- The date of manufacturing.
- Amount of chemical compounds filled in the container.
A chemical waste label does not mention or describe the experiment for which the chemicals were used for, scientists, teacher or students should have knowledge of the chemical composition by reading their names and evaluate themselves on which chemical should be used for which experiment.
Hence, the correct answer is "A description of the experiment the chemicals were used for."
Attached to this answer is the format of Isotope Notation that you can use for future reference. <em>(Please open)</em>
There are
8 Protons. The Atomic Number is the same number of an element's proton.
If you can see in the format, the mass number is calculated by adding the atomic number/protons and neutrons.
Mass number = 8 + 11Mass number = 19The image of the final answer is attached as well.
To calculate the new pressure, we can use Boyle’s law to relate these two scenarios (Boyle’s law is used because the temperature is assumed to remain constant). Boyle’s law is:
P1V1 = P2V2,
Where “P” is pressure and “V” is volume. The pressure and volume of the first scenario is 215 torr and 51 mL, respectively, and the second scenario has a volume of 18.5 L (18,500 mL) and the unknown pressure - let’s call that “x”. Plugging these into the equation:
(215 torr)(51 mL) =(“x” torr)(18,500 mL)
x = 0.593 torr
The final pressure exerted by the gas would be 0.593 torr.
Hope this helps!
Answer:
- Increased volume of particles in the container
- greater vibration of particles
Explanation:
At higher temperature, the particles of the gas would be more active and vibrate more, or even have greater collisions. Alex can indicate this in the altered model to depict higher temperature.
Consequently, Charles law gives meaning to why there would be an increased volume of gas in the stable pressurized container, if the temperature were to be increased.
I hope this explanation was clear and concise?
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