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soldier1979 [14.2K]
2 years ago
12

How many atoms of S are in 98.0 grams of hydrosulfuric acid?

Chemistry
1 answer:
noname [10]2 years ago
7 0
<h2>Answer:6.022\times 10^{23}</h2>

Explanation:

The formula for sulphuric acid is H_{2}SO_{4}.

Molecular mass of sulphuric acid is 2(2)+32+16(4)=98g

given weight=98g

Number of moles of sulphuric acid given is \frac{\text{given weight}}{molar mass}=\frac{98}{98}=1

The formula indicates that one mole of H_{2}SO_{4} contains 2 moles of H atoms,1 mole of S atoms,4 moles of O atoms.

So,the compound contains 1 mole of sulphur atoms.

1 mole of sulphur has 6.022\times 10^{23} atoms

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Complete combustion of a 0.600-g sample of a compound in a bomb calorimeter releases 24.0 kJ of heat. The bomb calorimeter has a
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Answer : The correct option is, 30.9^oC

Explanation :

Formula used :

q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

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m = mass of bomb calorimeter = 1.30 Kg

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Now put all the given values in the above formula, we get  the final temperature of the calorimeter.

q=m\times c\times (T_{final}-T_{initial})

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2 years ago
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You have a 16.0-oz. (473-mL) glass of lemonade with a concentration of 2.66 M. The lemonade sits out on your counter for a coupl
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<u>Answer:</u> The new concentration of lemonade is 3.90 M

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Molarity of lemonade solution = 2.66 M

Volume of solution = 473 mL

Putting values in equation 1, we get:

2.66M=\frac{\text{Moles of lemonade}\times 1000}{473}\\\\\text{Moles of lemonade}=\frac{2.66\times 473}{1000}=1.26mol

Now, calculating the new concentration of lemonade by using equation 1:

Moles of lemonade = 1.26 moles

Volume of solution = (473 - 150) mL = 323 mL

Putting values in equation 1, we get:

\text{New concentration of lemonade}=\frac{1.26\times 1000}{323}\\\\\text{New concentration of lemonade}=3.90M

Hence, the new concentration of lemonade is 3.90 M

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