To determine the mass of the hydrogen gas that was collected, we calculate for the moles of hydrogen gas from the conditions given. In order to do this, we need an equation which would relate pressure, volume and temperature. For simplicity, we assume the gas is an ideal gas so we use the equation PV = nRT where P is the pressure, V is the volume, n is the number of moles of the gas, T is the temperature and R is the universal gas constant. We calculate as follows:
PV = nRT
n = PV / RT
n = (18.6/760) (7.80) / 0.08205 ( 21 + 273.15)
n = 0.0079 mol
Mass = 0.0079 mol ( 18.02 g / mol ) = 0.1425 g H2
Answer:
Thus, when the volume of the gas is exposed to a temperature above -273.15 K, the volume increases linearly with the temperature.
Explanation:
The expression for Charles's Law is shown below:

This states that the volume of the gas is directly proportional to the absolute temperature keeping the pressure conditions and the moles of the gas constant.
<u>Thus, when the volume of the gas is exposed to a temperature above -273.15 K, the volume increases linearly with the temperature. </u>
<u>For example , if the temperature of the gas is reduced to half, the volume also reduced to half. </u>
<u>At -273.15 K, according to Charles's law, it is possible to make the volume of an ideal gas = 0.</u>
Molarity is expressed as
the number of moles of solute per volume of the solution. For example, we are
given a solution of 2M NaOH this describes a solution that has 2 moles of NaOH
per 1 L volume of the solution. We calculate as follows:
0.115 M = n mol KBr / .55 L solution
n = 0.06325 mol KBr
mass = 0.06325 mol KBr (119 g / mol) = 7.53 g KBr
Answer:
Explanation:
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